let n, m, i, j be Nat; ( |.(i - j).| + |.(n - m).| = 1 iff ( ( |.(i - j).| = 1 & n = m ) or ( |.(n - m).| = 1 & i = j ) ) )
thus
( not |.(i - j).| + |.(n - m).| = 1 or ( |.(i - j).| = 1 & n = m ) or ( |.(n - m).| = 1 & i = j ) )
( ( ( |.(i - j).| = 1 & n = m ) or ( |.(n - m).| = 1 & i = j ) ) implies |.(i - j).| + |.(n - m).| = 1 )proof
assume A1:
|.(i - j).| + |.(n - m).| = 1
;
( ( |.(i - j).| = 1 & n = m ) or ( |.(n - m).| = 1 & i = j ) )
now ( ( |.(i - j).| = 1 & n = m ) or ( |.(n - m).| = 1 & i = j ) )per cases
( n = m or n <> m )
;
suppose A3:
n <> m
;
( ( |.(i - j).| = 1 & n = m ) or ( |.(n - m).| = 1 & i = j ) )now ( ( |.(i - j).| = 1 & n = m ) or ( |.(n - m).| = 1 & i = j ) )per cases
( n < m or n > m )
by A3, XXREAL_0:1;
suppose A4:
n < m
;
( ( |.(i - j).| = 1 & n = m ) or ( |.(n - m).| = 1 & i = j ) )reconsider l =
m - n as
Element of
NAT by INT_1:5, A4;
0 < l
by A4, XREAL_1:50;
then A5:
0 + 1
<= l
by NAT_1:13;
A6:
|.(- (m - n)).| = |.l.|
by COMPLEX1:52;
then A7:
|.(n - m).| = |.l.|
;
A8:
|.l.| = l
by ABSVALUE:def 1;
then A9:
l <= 1
by A1, A6, COMPLEX1:46, XREAL_1:31;
then
l = 1
by A5, XXREAL_0:1;
then
i - j = 0
by A1, A8, A7, ABSVALUE:2;
hence
( (
|.(i - j).| = 1 &
n = m ) or (
|.(n - m).| = 1 &
i = j ) )
by A6, A5, A8, A9, XXREAL_0:1;
verum end; end; end; hence
( (
|.(i - j).| = 1 &
n = m ) or (
|.(n - m).| = 1 &
i = j ) )
;
verum end; end; end;
hence
( (
|.(i - j).| = 1 &
n = m ) or (
|.(n - m).| = 1 &
i = j ) )
;
verum
end;
assume A14:
( ( |.(i - j).| = 1 & n = m ) or ( |.(n - m).| = 1 & i = j ) )
; |.(i - j).| + |.(n - m).| = 1
hence
|.(i - j).| + |.(n - m).| = 1
; verum