let SAS be Semi_Affine_Space; for a, b, c, d, r, s being Element of SAS st congr r,s,a,b & congr r,s,c,d holds
congr a,b,c,d
let a, b, c, d, r, s be Element of SAS; ( congr r,s,a,b & congr r,s,c,d implies congr a,b,c,d )
assume that
A1:
congr r,s,a,b
and
A2:
congr r,s,c,d
; congr a,b,c,d
A3:
now ( r <> s & not r,s,a are_collinear & not r,s,c are_collinear implies congr a,b,c,d )assume that
r <> s
and A4:
( not
r,
s,
a are_collinear & not
r,
s,
c are_collinear )
;
congr a,b,c,d
(
parallelogram r,
s,
a,
b &
parallelogram r,
s,
c,
d )
by A1, A2, A4, Th59;
hence
congr a,
b,
c,
d
;
verum end;
A5:
now ( r <> s & r,s,c are_collinear implies congr a,b,c,d )assume that A6:
r <> s
and A7:
r,
s,
c are_collinear
;
congr a,b,c,dconsider p,
q being
Element of
SAS such that A8:
parallelogram p,
q,
r,
s
and A9:
parallelogram p,
q,
a,
b
by A1, A6;
parallelogram p,
q,
c,
d
by A2, A7, A8, Th61;
hence
congr a,
b,
c,
d
by A9;
verum end;
A10:
now ( r <> s & r,s,a are_collinear implies congr a,b,c,d )assume that A11:
r <> s
and A12:
r,
s,
a are_collinear
;
congr a,b,c,dconsider p,
q being
Element of
SAS such that A13:
parallelogram p,
q,
r,
s
and A14:
parallelogram p,
q,
c,
d
by A2, A11;
parallelogram p,
q,
a,
b
by A1, A12, A13, Th61;
hence
congr a,
b,
c,
d
by A14;
verum end;
( r = s implies congr a,b,c,d )
by A1, A2, Th54;
hence
congr a,b,c,d
by A10, A5, A3; verum