let SAS be Semi_Affine_Space; for a, b, c, d being Element of SAS st parallelogram a,b,c,d holds
not a,d // b,c
let a, b, c, d be Element of SAS; ( parallelogram a,b,c,d implies not a,d // b,c )
assume A1:
parallelogram a,b,c,d
; not a,d // b,c
then
not a,b,c are_collinear
;
then A2:
not a,b // a,c
;
( a,b // c,d & a,c // b,d )
by A1;
hence
not a,d // b,c
by A2, Def1; verum