let G, x be set ; ( card (union G) = 1 implies G is pairfree )
assume A1:
card (union G) = 1
; G is pairfree
assume
not G is pairfree
; contradiction
then
PairsOf G <> {}
;
then consider e being object such that
A2:
e in PairsOf G
by XBOOLE_0:def 1;
consider x, y being set such that
A3:
x <> y
and
A4:
x in union G
and
A5:
y in union G
and
e = {x,y}
by A2, Th11;
consider w being object such that
A6:
union G = {w}
by A1, CARD_2:42;
x = w
by A4, A6, TARSKI:def 1;
hence
contradiction
by A3, A5, A6, TARSKI:def 1; verum