assume A2:
( for a being set holds P1[a] or ex b being set st P2[b] )
; contradiction
per cases
( ex b being set st P2[b] or for a being set holds P1[a] )
by A2;
suppose
not for
b being
set holds
P2[
b]
;
contradictionthen consider b being
set such that A3:
P2[
b]
;
now for d being set holds not d = blet d be
set ;
not d = bassume
d = b
;
contradiction
ex
a being
set st
(
P1[
a] &
P2[
b] )
by A1;
hence
contradiction
by A3;
verum end; hence
contradiction
;
verum end; suppose A4:
for
a being
set holds
P1[
a]
;
contradictionnow for b being set holds contradictionlet b be
set ;
contradiction
ex
a being
set st
(
P1[
a] &
P2[
b] )
by A1;
hence
contradiction
by A4;
verum end; hence
contradiction
;
verum end; end;