defpred S1[ object , object ] means for x, y being object st $1 = [x,y] holds
( ( P1[x,y] implies $2 = F4(x,y) ) & ( P2[x,y] implies $2 = F5(x,y) ) );
defpred S2[ object ] means for x, y being object holds
( not $1 = [x,y] or P1[x,y] or P2[x,y] );
consider K being set such that
A4:
for z being object holds
( z in K iff ( z in [:F1(),F2():] & S2[z] ) )
from XBOOLE_0:sch 1();
A5:
for x1 being object st x1 in K holds
ex z being object st S1[x1,z]
proof
let x1 be
object ;
( x1 in K implies ex z being object st S1[x1,z] )
assume A6:
x1 in K
;
ex z being object st S1[x1,z]
then
x1 in [:F1(),F2():]
by A4;
then consider n9,
m9 being
object such that A7:
(
n9 in F1() &
m9 in F2() )
and A8:
x1 = [n9,m9]
by ZFMISC_1:def 2;
now ex z being object st
for x, y being object st x1 = [x,y] holds
( ( P1[x,y] implies z = F4(x,y) ) & ( P2[x,y] implies z = F5(x,y) ) )per cases
( P1[n9,m9] or P2[n9,m9] )
by A4, A6, A8;
suppose A9:
P1[
n9,
m9]
;
ex z being object st
for x, y being object st x1 = [x,y] holds
( ( P1[x,y] implies z = F4(x,y) ) & ( P2[x,y] implies z = F5(x,y) ) )take z =
F4(
n9,
m9);
for x, y being object st x1 = [x,y] holds
( ( P1[x,y] implies z = F4(x,y) ) & ( P2[x,y] implies z = F5(x,y) ) )let x,
y be
object ;
( x1 = [x,y] implies ( ( P1[x,y] implies z = F4(x,y) ) & ( P2[x,y] implies z = F5(x,y) ) ) )assume
x1 = [x,y]
;
( ( P1[x,y] implies z = F4(x,y) ) & ( P2[x,y] implies z = F5(x,y) ) )then
(
n9 = x &
m9 = y )
by A8, XTUPLE_0:1;
hence
( (
P1[
x,
y] implies
z = F4(
x,
y) ) & (
P2[
x,
y] implies
z = F5(
x,
y) ) )
by A1, A7, A9;
verum end; suppose A10:
P2[
n9,
m9]
;
ex z being object st
for x, y being object st x1 = [x,y] holds
( ( P1[x,y] implies z = F4(x,y) ) & ( P2[x,y] implies z = F5(x,y) ) )take z =
F5(
n9,
m9);
for x, y being object st x1 = [x,y] holds
( ( P1[x,y] implies z = F4(x,y) ) & ( P2[x,y] implies z = F5(x,y) ) )let x,
y be
object ;
( x1 = [x,y] implies ( ( P1[x,y] implies z = F4(x,y) ) & ( P2[x,y] implies z = F5(x,y) ) ) )assume
x1 = [x,y]
;
( ( P1[x,y] implies z = F4(x,y) ) & ( P2[x,y] implies z = F5(x,y) ) )then
(
n9 = x &
m9 = y )
by A8, XTUPLE_0:1;
hence
( (
P1[
x,
y] implies
z = F4(
x,
y) ) & (
P2[
x,
y] implies
z = F5(
x,
y) ) )
by A1, A7, A10;
verum end; end; end;
hence
ex
z being
object st
S1[
x1,
z]
;
verum
end;
consider f being Function such that
A11:
( dom f = K & ( for z being object st z in K holds
S1[z,f . z] ) )
from CLASSES1:sch 1(A5);
A12:
rng f c= F3()
K c= [:F1(),F2():]
by A4;
then reconsider f = f as PartFunc of [:F1(),F2():],F3() by A11, A12, RELSET_1:4;
take
f
; ( ( for x, y being object holds
( [x,y] in dom f iff ( x in F1() & y in F2() & ( P1[x,y] or P2[x,y] ) ) ) ) & ( for x, y being object st [x,y] in dom f holds
( ( P1[x,y] implies f . [x,y] = F4(x,y) ) & ( P2[x,y] implies f . [x,y] = F5(x,y) ) ) ) )
thus
for x, y being object holds
( [x,y] in dom f iff ( x in F1() & y in F2() & ( P1[x,y] or P2[x,y] ) ) )
for x, y being object st [x,y] in dom f holds
( ( P1[x,y] implies f . [x,y] = F4(x,y) ) & ( P2[x,y] implies f . [x,y] = F5(x,y) ) )proof
let x,
y be
object ;
( [x,y] in dom f iff ( x in F1() & y in F2() & ( P1[x,y] or P2[x,y] ) ) )
thus
(
[x,y] in dom f implies (
x in F1() &
y in F2() & (
P1[
x,
y] or
P2[
x,
y] ) ) )
by A4, A11, ZFMISC_1:87;
( x in F1() & y in F2() & ( P1[x,y] or P2[x,y] ) implies [x,y] in dom f )
assume that A19:
(
x in F1() &
y in F2() )
and A20:
(
P1[
x,
y] or
P2[
x,
y] )
;
[x,y] in dom f
A21:
now for z9, q9 being object holds
( not [x,y] = [z9,q9] or P1[z9,q9] or P2[z9,q9] )let z9,
q9 be
object ;
( not [x,y] = [z9,q9] or P1[z9,q9] or P2[z9,q9] )assume A22:
[x,y] = [z9,q9]
;
( P1[z9,q9] or P2[z9,q9] )then
x = z9
by XTUPLE_0:1;
hence
(
P1[
z9,
q9] or
P2[
z9,
q9] )
by A20, A22, XTUPLE_0:1;
verum end;
[x,y] in [:F1(),F2():]
by A19, ZFMISC_1:87;
hence
[x,y] in dom f
by A4, A11, A21;
verum
end;
let x, y be object ; ( [x,y] in dom f implies ( ( P1[x,y] implies f . [x,y] = F4(x,y) ) & ( P2[x,y] implies f . [x,y] = F5(x,y) ) ) )
assume
[x,y] in dom f
; ( ( P1[x,y] implies f . [x,y] = F4(x,y) ) & ( P2[x,y] implies f . [x,y] = F5(x,y) ) )
hence
( ( P1[x,y] implies f . [x,y] = F4(x,y) ) & ( P2[x,y] implies f . [x,y] = F5(x,y) ) )
by A11; verum