let E be non empty finite set ; for A, B, C being Event of E st 0 < prob (B /\ C) & 0 < prob C holds
prob ((A /\ B) /\ C) = ((prob (A,(B /\ C))) * (prob (B,C))) * (prob C)
let A, B, C be Event of E; ( 0 < prob (B /\ C) & 0 < prob C implies prob ((A /\ B) /\ C) = ((prob (A,(B /\ C))) * (prob (B,C))) * (prob C) )
assume that
A1:
0 < prob (B /\ C)
and
A2:
0 < prob C
; prob ((A /\ B) /\ C) = ((prob (A,(B /\ C))) * (prob (B,C))) * (prob C)
A3:
prob (B /\ C) = (prob (B,C)) * (prob C)
by A2, XCMPLX_1:87;
prob ((A /\ B) /\ C) = prob (A /\ (B /\ C))
by XBOOLE_1:16;
then
prob ((A /\ B) /\ C) = (prob (A,(B /\ C))) * (prob (B /\ C))
by A1, XCMPLX_1:87;
hence
prob ((A /\ B) /\ C) = ((prob (A,(B /\ C))) * (prob (B,C))) * (prob C)
by A3; verum