let E be non empty finite set ; for A, B being Event of E st 0 < prob B & A c= B holds
prob (A,B) = (prob A) / (prob B)
let A, B be Event of E; ( 0 < prob B & A c= B implies prob (A,B) = (prob A) / (prob B) )
assume that
A1:
0 < prob B
and
A2:
A c= B
; prob (A,B) = (prob A) / (prob B)
prob (A,B) = 1 - ((prob (B \ A)) / (prob B))
by A1, Th36;
then
prob (A,B) = 1 - (((prob B) - (prob A)) / (prob B))
by A2, Th24;
then
prob (A,B) = 1 - (((prob B) / (prob B)) - ((prob A) / (prob B)))
by XCMPLX_1:120;
then
prob (A,B) = 1 - (1 - ((prob A) / (prob B)))
by A1, XCMPLX_1:60;
hence
prob (A,B) = (prob A) / (prob B)
; verum