let R be Ring; for a, b being Element of R holds
( a | R = b | R iff a = b )
let a, b be Element of R; ( a | R = b | R iff a = b )
now ( a | R = b | R implies a = b )assume
a | R = b | R
;
a = bhence a =
(b | R) . 0
by Th28
.=
b
by Th28
;
verum end;
hence
( a | R = b | R iff a = b )
; verum