let x, y, X, Y, Z be set ; ( x `1_3 = y `1_3 & x `2_3 = y `2_3 & x `3_3 = y `3_3 & y in [:X,Y,Z:] & x in [:X,Y,Z:] implies x = y )
assume A1:
( x `1_3 = y `1_3 & x `2_3 = y `2_3 & x `3_3 = y `3_3 & y in [:X,Y,Z:] )
; ( not x in [:X,Y,Z:] or x = y )
assume
x in [:X,Y,Z:]
; x = y
hence x =
[(x `1_3),(x `2_3),(x `3_3)]
by Th3
.=
y
by A1, Th3
;
verum