let B, A be RearrangmentGen of D; ( ( for m being Nat st 1 <= m & m <= (len B) - 1 holds
B . m = D \ (A . ((len A) - m)) ) implies for m being Nat st 1 <= m & m <= (len A) - 1 holds
A . m = D \ (B . ((len B) - m)) )
assume A38:
for m being Nat st 1 <= m & m <= (len B) - 1 holds
B . m = D \ (A . ((len A) - m))
; for m being Nat st 1 <= m & m <= (len A) - 1 holds
A . m = D \ (B . ((len B) - m))
let m be Nat; ( 1 <= m & m <= (len A) - 1 implies A . m = D \ (B . ((len B) - m)) )
assume A39:
( 1 <= m & m <= (len A) - 1 )
; A . m = D \ (B . ((len B) - m))
A40:
len A = card D
by Th1;
A41:
len B = card D
by Th1;
(len A) - 1 < len A
by XREAL_1:44;
then A42:
m < len A
by A39, XXREAL_0:2;
then
(len A) - m in NAT
by INT_1:5;
then reconsider n = (len B) - m as Nat by A40, A41;
A43:
(len A) - n = m
by A40, A41;
m + 1 <= len A
by A39, XREAL_1:19;
then A44:
1 <= n
by A40, A41, XREAL_1:19;
A45:
n <= (len B) - 1
by A39, XREAL_1:10;
(len A) - n in dom A
by A43, A39, A42, FINSEQ_3:25;
then A46:
A . ((len A) - n) c= D
by Lm5;
thus A . m =
A . ((len A) - n)
by A40, A41
.=
D /\ (A . ((len A) - n))
by A46, XBOOLE_1:28
.=
D \ (D \ (A . ((len A) - n)))
by XBOOLE_1:48
.=
D \ (B . ((len B) - m))
by A44, A45, A38
; verum