let F be Field; for p being Element of the carrier of (Polynom-Ring F) st deg p is odd holds
ex q being monic non constant Element of the carrier of (Polynom-Ring F) st
( q divides p & q is irreducible & deg q is odd )
let p1 be Element of the carrier of (Polynom-Ring F); ( deg p1 is odd implies ex q being monic non constant Element of the carrier of (Polynom-Ring F) st
( q divides p1 & q is irreducible & deg q is odd ) )
assume AS:
deg p1 is odd
; ex q being monic non constant Element of the carrier of (Polynom-Ring F) st
( q divides p1 & q is irreducible & deg q is odd )
per cases
( p1 is zero or not p1 is zero )
;
suppose
not
p1 is
zero
;
ex q being monic non constant Element of the carrier of (Polynom-Ring F) st
( q divides p1 & q is irreducible & deg q is odd )then reconsider p =
p1 as non
zero Element of the
carrier of
(Polynom-Ring F) ;
defpred S1[
Nat]
means for
p being non
zero Element of the
carrier of
(Polynom-Ring F) st
deg p = (2 * $1) + 1 holds
ex
q being
monic non
constant Element of the
carrier of
(Polynom-Ring F) st
(
q divides p &
q is
irreducible &
deg q is
odd );
IS:
now for k being Nat st ( for n being Nat st n < k holds
S1[n] ) holds
S1[k]let k be
Nat;
( ( for n being Nat st n < k holds
S1[n] ) implies S1[b1] )assume AS1:
for
n being
Nat st
n < k holds
S1[
n]
;
S1[b1]per cases
( k = 0 or k > 0 )
;
suppose
k > 0
;
S1[b1]now for p being non zero Element of the carrier of (Polynom-Ring F) st deg p = (2 * k) + 1 holds
ex q being monic non constant Element of the carrier of (Polynom-Ring F) st
( q divides p & q is irreducible & deg q is odd )let p be non
zero Element of the
carrier of
(Polynom-Ring F);
( deg p = (2 * k) + 1 implies ex q being monic non constant Element of the carrier of (Polynom-Ring F) st
( b2 divides q & b2 is irreducible & deg b2 is odd ) )assume AS3:
deg p = (2 * k) + 1
;
ex q being monic non constant Element of the carrier of (Polynom-Ring F) st
( b2 divides q & b2 is irreducible & deg b2 is odd )then
not
p is
constant
by RING_4:def 4;
then consider q being
monic non
constant Element of the
carrier of
(Polynom-Ring F) such that A:
(
q divides p &
q is
irreducible )
by lem22;
per cases
( deg q is odd or deg q is even )
;
suppose B:
deg q is
even
;
ex q being monic non constant Element of the carrier of (Polynom-Ring F) st
( b2 divides q & b2 is irreducible & deg b2 is odd )consider r being
Polynomial of
F such that C:
q *' r = p
by A, RING_4:1;
(
q <> 0_. F &
r <> 0_. F )
by C;
then I:
(deg q) + (deg r) = deg p
by C, HURWITZ:23;
then
deg r is
odd
by AS3, B;
then consider i being
Integer such that E:
deg r = (2 * i) + 1
by ABIAN:1;
now not i < 0 assume E2:
i < 0
;
contradiction
not
r is
zero
by C;
hence
contradiction
by E, E2, INT_1:7;
verum end; then reconsider i =
i as
Element of
NAT by INT_1:3;
reconsider r =
r as
Element of the
carrier of
(Polynom-Ring F) by POLYNOM3:def 10;
reconsider r =
r as non
zero Element of the
carrier of
(Polynom-Ring F) by C;
(
deg r <= deg p &
deg r <> deg p )
by C, I, RING_4:def 4, RING_4:1, RING_5:13;
then
(2 * i) + 1
< (2 * k) + 1
by AS3, E, XXREAL_0:1;
then
((2 * i) + 1) - 1
< ((2 * k) + 1) - 1
by XREAL_1:9;
then
(2 * i) - (2 * k) < (2 * k) - (2 * k)
by XREAL_1:9;
then
2
* (i - k) < 0
;
then
i - k < 0
;
then
(i - k) + k < 0 + k
by XREAL_1:6;
then consider s being
monic non
constant Element of the
carrier of
(Polynom-Ring F) such that F:
(
s divides r &
s is
irreducible &
deg s is
odd )
by E, AS1;
consider t being
Polynomial of
F such that H:
s *' t = r
by F, RING_4:1;
s *' (t *' q) = p
by H, C, POLYNOM3:33;
hence
ex
q being
monic non
constant Element of the
carrier of
(Polynom-Ring F) st
(
q divides p &
q is
irreducible &
deg q is
odd )
by F, RING_4:1;
verum end; end; end; hence
S1[
k]
;
verum end; end; end; I:
for
k being
Nat holds
S1[
k]
from NAT_1:sch 4(IS);
consider i being
Integer such that H:
deg p = (2 * i) + 1
by AS, ABIAN:1;
i >= 0
by H, INT_1:7;
then reconsider i =
i as
Element of
NAT by INT_1:3;
deg p = (2 * i) + 1
by H;
hence
ex
q being
monic non
constant Element of the
carrier of
(Polynom-Ring F) st
(
q divides p1 &
q is
irreducible &
deg q is
odd )
by I;
verum end; end;