let X be non empty set ; for A being finite Subset of X
for a being Element of X st not a in A holds
for B being finite Subset of X st B = {a} \/ A holds
for R being Order of X st R linearly_orders B holds
for k being Element of NAT st k + 1 in dom (SgmX (R,B)) & (SgmX (R,B)) /. (k + 1) = a holds
SgmX (R,B) = Ins ((SgmX (R,A)),k,a)
let A be finite Subset of X; for a being Element of X st not a in A holds
for B being finite Subset of X st B = {a} \/ A holds
for R being Order of X st R linearly_orders B holds
for k being Element of NAT st k + 1 in dom (SgmX (R,B)) & (SgmX (R,B)) /. (k + 1) = a holds
SgmX (R,B) = Ins ((SgmX (R,A)),k,a)
let a be Element of X; ( not a in A implies for B being finite Subset of X st B = {a} \/ A holds
for R being Order of X st R linearly_orders B holds
for k being Element of NAT st k + 1 in dom (SgmX (R,B)) & (SgmX (R,B)) /. (k + 1) = a holds
SgmX (R,B) = Ins ((SgmX (R,A)),k,a) )
assume A1:
not a in A
; for B being finite Subset of X st B = {a} \/ A holds
for R being Order of X st R linearly_orders B holds
for k being Element of NAT st k + 1 in dom (SgmX (R,B)) & (SgmX (R,B)) /. (k + 1) = a holds
SgmX (R,B) = Ins ((SgmX (R,A)),k,a)
let B be finite Subset of X; ( B = {a} \/ A implies for R being Order of X st R linearly_orders B holds
for k being Element of NAT st k + 1 in dom (SgmX (R,B)) & (SgmX (R,B)) /. (k + 1) = a holds
SgmX (R,B) = Ins ((SgmX (R,A)),k,a) )
assume A2:
B = {a} \/ A
; for R being Order of X st R linearly_orders B holds
for k being Element of NAT st k + 1 in dom (SgmX (R,B)) & (SgmX (R,B)) /. (k + 1) = a holds
SgmX (R,B) = Ins ((SgmX (R,A)),k,a)
let R be Order of X; ( R linearly_orders B implies for k being Element of NAT st k + 1 in dom (SgmX (R,B)) & (SgmX (R,B)) /. (k + 1) = a holds
SgmX (R,B) = Ins ((SgmX (R,A)),k,a) )
assume A3:
R linearly_orders B
; for k being Element of NAT st k + 1 in dom (SgmX (R,B)) & (SgmX (R,B)) /. (k + 1) = a holds
SgmX (R,B) = Ins ((SgmX (R,A)),k,a)
let k be Element of NAT ; ( k + 1 in dom (SgmX (R,B)) & (SgmX (R,B)) /. (k + 1) = a implies SgmX (R,B) = Ins ((SgmX (R,A)),k,a) )
assume that
A4:
k + 1 in dom (SgmX (R,B))
and
A5:
(SgmX (R,B)) /. (k + 1) = a
; SgmX (R,B) = Ins ((SgmX (R,A)),k,a)
set sgb = SgmX (R,B);
set sga = Ins ((SgmX (R,A)),k,a);
A6:
dom (SgmX (R,B)) = Seg (len (SgmX (R,B)))
by FINSEQ_1:def 3;
then
k + 1 <= len (SgmX (R,B))
by A4, FINSEQ_1:1;
then A7:
(k + 1) - 1 <= (len (SgmX (R,B))) - 1
by XREAL_1:9;
A8:
(k + 1) - 1 = k + 0
;
A9: len (SgmX (R,B)) =
card B
by A3, Th10
.=
(card A) + 1
by A1, A2, CARD_2:41
.=
(len (SgmX (R,A))) + 1
by A2, A3, Lm6, Th10
;
then A10: dom (SgmX (R,B)) =
Seg (len (Ins ((SgmX (R,A)),k,a)))
by A6, FINSEQ_5:69
.=
dom (Ins ((SgmX (R,A)),k,a))
by FINSEQ_1:def 3
;
A11:
for i being Nat st 1 <= i & i <= len (SgmX (R,B)) holds
(SgmX (R,B)) . i = (Ins ((SgmX (R,A)),k,a)) . i
proof
let i be
Nat;
( 1 <= i & i <= len (SgmX (R,B)) implies (SgmX (R,B)) . i = (Ins ((SgmX (R,A)),k,a)) . i )
assume that A12:
1
<= i
and A13:
i <= len (SgmX (R,B))
;
(SgmX (R,B)) . i = (Ins ((SgmX (R,A)),k,a)) . i
A14:
i in Seg (len (SgmX (R,B)))
by A12, A13, FINSEQ_1:1;
A15:
i in dom (SgmX (R,B))
by FINSEQ_3:25, A12, A13;
A16:
i in dom (Ins ((SgmX (R,A)),k,a))
by A10, A14, FINSEQ_1:def 3;
per cases
( i = k + 1 or i <> k + 1 )
;
suppose A17:
i = k + 1
;
(SgmX (R,B)) . i = (Ins ((SgmX (R,A)),k,a)) . ithen
a = (SgmX (R,B)) . i
by A5, PARTFUN1:def 6, A15;
hence (SgmX (R,B)) . i =
(Ins ((SgmX (R,A)),k,a)) . (k + 1)
by A9, A7, FINSEQ_5:73
.=
(Ins ((SgmX (R,A)),k,a)) . i
by A17
;
verum end; suppose A18:
i <> k + 1
;
(SgmX (R,B)) . i = (Ins ((SgmX (R,A)),k,a)) . inow ( ( i < k + 1 & (SgmX (R,B)) . i = (Ins ((SgmX (R,A)),k,a)) . i ) or ( k + 1 <= i & (SgmX (R,B)) . i = (Ins ((SgmX (R,A)),k,a)) . i ) )per cases
( i < k + 1 or k + 1 <= i )
;
case
i < k + 1
;
(SgmX (R,B)) . i = (Ins ((SgmX (R,A)),k,a)) . ithen A19:
i <= k
by NAT_1:13;
(SgmX (R,A)) | (Seg k) is
FinSequence
by FINSEQ_1:15;
then
dom ((SgmX (R,A)) | (Seg k)) = Seg k
by A9, A7, FINSEQ_1:17;
then SS:
i in dom ((SgmX (R,A)) | (Seg k))
by A12, A19, FINSEQ_1:1;
then A20:
i in dom ((SgmX (R,A)) | k)
by FINSEQ_1:def 16;
A:
i in dom (SgmX (R,A))
by RELAT_1:57, SS;
thus (SgmX (R,B)) . i =
(SgmX (R,B)) /. i
by A15, PARTFUN1:def 6
.=
(SgmX (R,A)) /. i
by A1, A2, A3, A4, A5, A8, A12, A14, A19, Th76
.=
(SgmX (R,A)) . i
by PARTFUN1:def 6, A
.=
(Ins ((SgmX (R,A)),k,a)) . i
by A20, FINSEQ_5:72
;
verum end; case A21:
k + 1
<= i
;
(SgmX (R,B)) . i = (Ins ((SgmX (R,A)),k,a)) . ithen a21:
k + 1
< i
by A18, XXREAL_0:1;
1
- 1
<= i - 1
by A12, XREAL_1:9;
then reconsider i9 =
i - 1 as
Element of
NAT by INT_1:3;
A22:
i9 + 1
= i + 0
;
F:
1
<= k + 1
by FINSEQ_3:25, A4;
k + 1
< i9 + 1
by a21;
then
1
< i9 + 1
by F, XXREAL_0:2;
then
1
+ 1
<= i9 + 1
by NAT_1:13;
then F1:
1
<= i9
by XREAL_1:6;
Z2:
i9 + 1
in dom (Ins ((SgmX (R,A)),k,a))
by A16;
then
i9 + 1
<= len (Ins ((SgmX (R,A)),k,a))
by FINSEQ_3:25;
then
i9 + 1
<= (len (SgmX (R,A))) + 1
by FINSEQ_5:69;
then
i9 <= len (SgmX (R,A))
by XREAL_1:6;
then F2:
i9 in dom (SgmX (R,A))
by FINSEQ_3:25, F1;
k + 1
< i
by A18, A21, XXREAL_0:1;
then A23:
k + 1
<= i9
by A22, NAT_1:13;
A24:
i9 <= (len (SgmX (R,B))) - 1
by A13, XREAL_1:9;
thus (SgmX (R,B)) . i =
(SgmX (R,B)) /. (i9 + 1)
by A15, PARTFUN1:def 6
.=
(SgmX (R,A)) /. i9
by A1, A2, A3, A4, A5, A9, A24, A23, Th77
.=
(SgmX (R,A)) . i9
by PARTFUN1:def 6, F2
.=
(Ins ((SgmX (R,A)),k,a)) . (i9 + 1)
by A9, A24, A23, FINSEQ_5:74
.=
(Ins ((SgmX (R,A)),k,a)) /. (i9 + 1)
by Z2, PARTFUN1:def 6
.=
(Ins ((SgmX (R,A)),k,a)) . i
by A16, PARTFUN1:def 6
;
verum end; end; end; hence
(SgmX (R,B)) . i = (Ins ((SgmX (R,A)),k,a)) . i
;
verum end; end;
end;
len (SgmX (R,B)) = len (Ins ((SgmX (R,A)),k,a))
by A9, FINSEQ_5:69;
hence
SgmX (R,B) = Ins ((SgmX (R,A)),k,a)
by A11, FINSEQ_1:14; verum