let p, q be bag of n; ( ex k being Ordinal st
( p . k < q . k & ( for l being Ordinal st l in k holds
p . l = q . l ) ) implies for k being Ordinal holds
( not q . k < p . k or ex l being Ordinal st
( l in k & not q . l = p . l ) ) )
given k being Ordinal such that A1:
p . k < q . k
and
A2:
for l being Ordinal st l in k holds
p . l = q . l
; for k being Ordinal holds
( not q . k < p . k or ex l being Ordinal st
( l in k & not q . l = p . l ) )
given k1 being Ordinal such that A3:
q . k1 < p . k1
and
A4:
for l being Ordinal st l in k1 holds
q . l = p . l
; contradiction