set R = the InternalRel of [:P,Q:];
reconsider L = L as Relation of the carrier of P, the carrier of Q by YELLOW_3:def 2;
reconsider L1 = dom L as Subset of P ;
reconsider L2 = rng L as Subset of Q ;
set R2 = the InternalRel of Q;
for x, y being object st x in L2 & y in L2 & not [x,y] in the InternalRel of Q holds
[y,x] in the InternalRel of Q
proof
let x,
y be
object ;
( x in L2 & y in L2 & not [x,y] in the InternalRel of Q implies [y,x] in the InternalRel of Q )
assume B1:
(
x in L2 &
y in L2 )
;
( [x,y] in the InternalRel of Q or [y,x] in the InternalRel of Q )
then reconsider x =
x,
y =
y as
Element of
Q ;
consider p1 being
object such that B2:
[p1,x] in L
by XTUPLE_0:def 13, B1;
consider p2 being
object such that B3:
[p2,y] in L
by XTUPLE_0:def 13, B1;
(
p1 in L1 &
p2 in L1 )
by B2, B3, XTUPLE_0:def 12;
then reconsider p1 =
p1,
p2 =
p2 as
Element of
P ;
reconsider a =
[p1,x],
b =
[p2,y] as
Element of
[:P,Q:] ;
end;
hence
rng L is non empty Chain of Q
by ORDERS_2:def 7, RELAT_2:def 7; verum