set R = the InternalRel of [:P,Q:];
reconsider L = L as Relation of the carrier of P, the carrier of Q by YELLOW_3:def 2;
reconsider L1 = dom L as Subset of P ;
reconsider L2 = rng L as Subset of Q ;
set R1 = the InternalRel of P;
for x, y being object st x in L1 & y in L1 & not [x,y] in the InternalRel of P holds
[y,x] in the InternalRel of P
proof
let x,
y be
object ;
( x in L1 & y in L1 & not [x,y] in the InternalRel of P implies [y,x] in the InternalRel of P )
assume B1:
(
x in L1 &
y in L1 )
;
( [x,y] in the InternalRel of P or [y,x] in the InternalRel of P )
then reconsider x =
x,
y =
y as
Element of
P ;
consider q1 being
object such that B2:
[x,q1] in L
by XTUPLE_0:def 12, B1;
consider q2 being
object such that B3:
[y,q2] in L
by XTUPLE_0:def 12, B1;
(
q1 in L2 &
q2 in L2 )
by B2, B3, XTUPLE_0:def 13;
then reconsider q1 =
q1,
q2 =
q2 as
Element of
Q ;
reconsider a =
[x,q1] as
Element of
[:P,Q:] ;
reconsider b =
[y,q2] as
Element of
[:P,Q:] ;
end;
hence
dom L is non empty Chain of P
by ORDERS_2:def 7, RELAT_2:def 7; verum