let X, Y be non empty set ; for D being Subset of X
for I1, I2 being Function of X,Y
for J1, J2 being Function of [:X,Y,Y:],Y
for E1, E2 being Function of X,X
for f1, g1, f2, g2 being Function of X,Y st E1,E2 is_well_founded_with_minimal_set D & ( for x being Element of X holds
( ( x in D implies ( f1 . x = I1 . x & g1 . x = I2 . x ) ) & ( not x in D implies ( f1 . x = J1 . [x,(f1 . (E1 . x)),(g1 . (E2 . x))] & g1 . x = J2 . [x,(f1 . (E1 . x)),(g1 . (E2 . x))] ) ) ) ) & ( for x being Element of X holds
( ( x in D implies ( f2 . x = I1 . x & g2 . x = I2 . x ) ) & ( not x in D implies ( f2 . x = J1 . [x,(f2 . (E1 . x)),(g2 . (E2 . x))] & g2 . x = J2 . [x,(f2 . (E1 . x)),(g2 . (E2 . x))] ) ) ) ) holds
( f1 = f2 & g1 = g2 )
let D be Subset of X; for I1, I2 being Function of X,Y
for J1, J2 being Function of [:X,Y,Y:],Y
for E1, E2 being Function of X,X
for f1, g1, f2, g2 being Function of X,Y st E1,E2 is_well_founded_with_minimal_set D & ( for x being Element of X holds
( ( x in D implies ( f1 . x = I1 . x & g1 . x = I2 . x ) ) & ( not x in D implies ( f1 . x = J1 . [x,(f1 . (E1 . x)),(g1 . (E2 . x))] & g1 . x = J2 . [x,(f1 . (E1 . x)),(g1 . (E2 . x))] ) ) ) ) & ( for x being Element of X holds
( ( x in D implies ( f2 . x = I1 . x & g2 . x = I2 . x ) ) & ( not x in D implies ( f2 . x = J1 . [x,(f2 . (E1 . x)),(g2 . (E2 . x))] & g2 . x = J2 . [x,(f2 . (E1 . x)),(g2 . (E2 . x))] ) ) ) ) holds
( f1 = f2 & g1 = g2 )
let I1, I2 be Function of X,Y; for J1, J2 being Function of [:X,Y,Y:],Y
for E1, E2 being Function of X,X
for f1, g1, f2, g2 being Function of X,Y st E1,E2 is_well_founded_with_minimal_set D & ( for x being Element of X holds
( ( x in D implies ( f1 . x = I1 . x & g1 . x = I2 . x ) ) & ( not x in D implies ( f1 . x = J1 . [x,(f1 . (E1 . x)),(g1 . (E2 . x))] & g1 . x = J2 . [x,(f1 . (E1 . x)),(g1 . (E2 . x))] ) ) ) ) & ( for x being Element of X holds
( ( x in D implies ( f2 . x = I1 . x & g2 . x = I2 . x ) ) & ( not x in D implies ( f2 . x = J1 . [x,(f2 . (E1 . x)),(g2 . (E2 . x))] & g2 . x = J2 . [x,(f2 . (E1 . x)),(g2 . (E2 . x))] ) ) ) ) holds
( f1 = f2 & g1 = g2 )
let J1, J2 be Function of [:X,Y,Y:],Y; for E1, E2 being Function of X,X
for f1, g1, f2, g2 being Function of X,Y st E1,E2 is_well_founded_with_minimal_set D & ( for x being Element of X holds
( ( x in D implies ( f1 . x = I1 . x & g1 . x = I2 . x ) ) & ( not x in D implies ( f1 . x = J1 . [x,(f1 . (E1 . x)),(g1 . (E2 . x))] & g1 . x = J2 . [x,(f1 . (E1 . x)),(g1 . (E2 . x))] ) ) ) ) & ( for x being Element of X holds
( ( x in D implies ( f2 . x = I1 . x & g2 . x = I2 . x ) ) & ( not x in D implies ( f2 . x = J1 . [x,(f2 . (E1 . x)),(g2 . (E2 . x))] & g2 . x = J2 . [x,(f2 . (E1 . x)),(g2 . (E2 . x))] ) ) ) ) holds
( f1 = f2 & g1 = g2 )
let E1, E2 be Function of X,X; for f1, g1, f2, g2 being Function of X,Y st E1,E2 is_well_founded_with_minimal_set D & ( for x being Element of X holds
( ( x in D implies ( f1 . x = I1 . x & g1 . x = I2 . x ) ) & ( not x in D implies ( f1 . x = J1 . [x,(f1 . (E1 . x)),(g1 . (E2 . x))] & g1 . x = J2 . [x,(f1 . (E1 . x)),(g1 . (E2 . x))] ) ) ) ) & ( for x being Element of X holds
( ( x in D implies ( f2 . x = I1 . x & g2 . x = I2 . x ) ) & ( not x in D implies ( f2 . x = J1 . [x,(f2 . (E1 . x)),(g2 . (E2 . x))] & g2 . x = J2 . [x,(f2 . (E1 . x)),(g2 . (E2 . x))] ) ) ) ) holds
( f1 = f2 & g1 = g2 )
let f1, g1, f2, g2 be Function of X,Y; ( E1,E2 is_well_founded_with_minimal_set D & ( for x being Element of X holds
( ( x in D implies ( f1 . x = I1 . x & g1 . x = I2 . x ) ) & ( not x in D implies ( f1 . x = J1 . [x,(f1 . (E1 . x)),(g1 . (E2 . x))] & g1 . x = J2 . [x,(f1 . (E1 . x)),(g1 . (E2 . x))] ) ) ) ) & ( for x being Element of X holds
( ( x in D implies ( f2 . x = I1 . x & g2 . x = I2 . x ) ) & ( not x in D implies ( f2 . x = J1 . [x,(f2 . (E1 . x)),(g2 . (E2 . x))] & g2 . x = J2 . [x,(f2 . (E1 . x)),(g2 . (E2 . x))] ) ) ) ) implies ( f1 = f2 & g1 = g2 ) )
assume A0:
( E1,E2 is_well_founded_with_minimal_set D & ( for x being Element of X holds
( ( x in D implies ( f1 . x = I1 . x & g1 . x = I2 . x ) ) & ( not x in D implies ( f1 . x = J1 . [x,(f1 . (E1 . x)),(g1 . (E2 . x))] & g1 . x = J2 . [x,(f1 . (E1 . x)),(g1 . (E2 . x))] ) ) ) ) & ( for x being Element of X holds
( ( x in D implies ( f2 . x = I1 . x & g2 . x = I2 . x ) ) & ( not x in D implies ( f2 . x = J1 . [x,(f2 . (E1 . x)),(g2 . (E2 . x))] & g2 . x = J2 . [x,(f2 . (E1 . x)),(g2 . (E2 . x))] ) ) ) ) )
; ( f1 = f2 & g1 = g2 )
then consider l being Function of X,NAT such that
A1:
for x being Element of X holds
( ( l . x <= 0 implies x in D ) & ( not x in D implies ( l . (E1 . x) < l . x & l . (E2 . x) < l . x ) ) )
;
defpred S1[ Nat] means for x being Element of X st l . x <= $1 holds
( f1 . x = f2 . x & g1 . x = g2 . x );
A2:
S1[ 0 ]
proof
let x be
Element of
X;
( l . x <= 0 implies ( f1 . x = f2 . x & g1 . x = g2 . x ) )
assume
l . x <= 0
;
( f1 . x = f2 . x & g1 . x = g2 . x )
then B1:
x in D
by A1;
B2:
f1 . x =
I1 . x
by A0, B1
.=
f2 . x
by A0, B1
;
g1 . x =
I2 . x
by A0, B1
.=
g2 . x
by A0, B1
;
hence
(
f1 . x = f2 . x &
g1 . x = g2 . x )
by B2;
verum
end;
A3:
for k being Nat st S1[k] holds
S1[k + 1]
proof
let k be
Nat;
( S1[k] implies S1[k + 1] )
assume B0:
S1[
k]
;
S1[k + 1]
let x be
Element of
X;
( l . x <= k + 1 implies ( f1 . x = f2 . x & g1 . x = g2 . x ) )
assume B1:
l . x <= k + 1
;
( f1 . x = f2 . x & g1 . x = g2 . x )
per cases
( x in D or not x in D )
;
suppose C0:
not
x in D
;
( f1 . x = f2 . x & g1 . x = g2 . x )reconsider x1 =
E1 . x,
x2 =
E2 . x as
Element of
X ;
(
(l . x1) + 1
<= l . x &
(l . x2) + 1
<= l . x )
by NAT_1:13, A1, C0;
then
(
(l . x1) + 1
<= k + 1 &
(l . x2) + 1
<= k + 1 )
by B1, XXREAL_0:2;
then
(
l . x1 <= k &
l . x2 <= k )
by XREAL_1:8;
then C1:
(
f1 . x1 = f2 . x1 &
g1 . x2 = g2 . x2 )
by B0;
C2:
f1 . x =
J1 . [x,(f2 . x1),(g2 . x2)]
by A0, C0, C1
.=
f2 . x
by A0, C0
;
g1 . x =
J2 . [x,(f2 . x1),(g2 . x2)]
by A0, C0, C1
.=
g2 . x
by A0, C0
;
hence
(
f1 . x = f2 . x &
g1 . x = g2 . x )
by C2;
verum end; end;
end;
A4:
for k being Nat holds S1[k]
from NAT_1:sch 2(A2, A3);
for x being Element of X holds
( f1 . x = f2 . x & g1 . x = g2 . x )
proof
let x be
Element of
X;
( f1 . x = f2 . x & g1 . x = g2 . x )
reconsider k =
l . x as
Nat ;
l . x <= k
;
hence
(
f1 . x = f2 . x &
g1 . x = g2 . x )
by A4;
verum
end;
hence
( f1 = f2 & g1 = g2 )
; verum