let x, a, b be Real; for n being Element of NAT st a <> 0 & n is odd & Polynom (a,b,0,(x |^ n)) = 0 & not x = 0 holds
x = n -root (- (b / a))
let n be Element of NAT ; ( a <> 0 & n is odd & Polynom (a,b,0,(x |^ n)) = 0 & not x = 0 implies x = n -root (- (b / a)) )
assume that
A1:
a <> 0
and
A2:
n is odd
and
A3:
Polynom (a,b,0,(x |^ n)) = 0
; ( x = 0 or x = n -root (- (b / a)) )
hence
( x = 0 or x = n -root (- (b / a)) )
; verum