let p1, p2 be set ; ( ( for z being set holds
( z in p1 iff ex y being set st
( y in X & z = {t,y} ) ) ) & ( for z being set holds
( z in p2 iff ex y being set st
( y in X & z = {t,y} ) ) ) implies p1 = p2 )
assume that
A6:
for z being set holds
( z in p1 iff ex y being set st
( y in X & z = {t,y} ) )
and
A7:
for z being set holds
( z in p2 iff ex y being set st
( y in X & z = {t,y} ) )
; p1 = p2
hence
p1 = p2
by TARSKI:2; verum