let X be set ; :: thesis: ( 3 c= card X implies for x, y being object ex z being object st
( z in X & x <> z & y <> z ) )

assume 3 c= card X ; :: thesis: for x, y being object ex z being object st
( z in X & x <> z & y <> z )

then consider a, b, c being object such that
A1: a in X and
A2: b in X and
A3: c in X and
A4: a <> b and
A5: ( a <> c & b <> c ) by Th5;
let x, y be object ; :: thesis: ex z being object st
( z in X & x <> z & y <> z )

per cases ( ( x <> a & y <> a ) or ( x <> a & y = a & x = b ) or ( x <> a & y = a & x <> b ) or ( x = a & y <> a & y = b ) or ( x = a & y <> a & y <> b ) or ( x = a & y = a ) ) ;
suppose ( x <> a & y <> a ) ; :: thesis: ex z being object st
( z in X & x <> z & y <> z )

hence ex z being object st
( z in X & x <> z & y <> z ) by A1; :: thesis: verum
end;
suppose ( x <> a & y = a & x = b ) ; :: thesis: ex z being object st
( z in X & x <> z & y <> z )

hence ex z being object st
( z in X & x <> z & y <> z ) by A3, A5; :: thesis: verum
end;
suppose ( x <> a & y = a & x <> b ) ; :: thesis: ex z being object st
( z in X & x <> z & y <> z )

hence ex z being object st
( z in X & x <> z & y <> z ) by A2, A4; :: thesis: verum
end;
suppose ( x = a & y <> a & y = b ) ; :: thesis: ex z being object st
( z in X & x <> z & y <> z )

hence ex z being object st
( z in X & x <> z & y <> z ) by A3, A5; :: thesis: verum
end;
suppose ( x = a & y <> a & y <> b ) ; :: thesis: ex z being object st
( z in X & x <> z & y <> z )

hence ex z being object st
( z in X & x <> z & y <> z ) by A2, A4; :: thesis: verum
end;
suppose ( x = a & y = a ) ; :: thesis: ex z being object st
( z in X & x <> z & y <> z )

hence ex z being object st
( z in X & x <> z & y <> z ) by A2, A4; :: thesis: verum
end;
end;