let x, y be PartFunc of REAL,REAL; for Z being open Subset of REAL
for a, b being Real st x is continuous & y is differentiable & y `| Z is continuous & a <= b & ['a,b'] c= Z & Z c= dom x & Z c= dom y holds
integral ((x (#) (y `| Z)),a,b) <= (1 / 2) * (integral (((x (#) x) + ((y `| Z) (#) (y `| Z))),a,b))
let Z be open Subset of REAL; for a, b being Real st x is continuous & y is differentiable & y `| Z is continuous & a <= b & ['a,b'] c= Z & Z c= dom x & Z c= dom y holds
integral ((x (#) (y `| Z)),a,b) <= (1 / 2) * (integral (((x (#) x) + ((y `| Z) (#) (y `| Z))),a,b))
let a, b be Real; ( x is continuous & y is differentiable & y `| Z is continuous & a <= b & ['a,b'] c= Z & Z c= dom x & Z c= dom y implies integral ((x (#) (y `| Z)),a,b) <= (1 / 2) * (integral (((x (#) x) + ((y `| Z) (#) (y `| Z))),a,b)) )
assume that
A1:
x is continuous
and
A2:
y is differentiable
and
A3:
y `| Z is continuous
and
A4:
( a <= b & ['a,b'] c= Z & Z c= dom x & Z c= dom y )
; integral ((x (#) (y `| Z)),a,b) <= (1 / 2) * (integral (((x (#) x) + ((y `| Z) (#) (y `| Z))),a,b))
A5:
(x (#) (y `| Z)) | ['a,b'] is continuous
by A1, A3;
y is_differentiable_on Z
by A2, A4, FDIFF_1:28;
then A6:
dom (y `| Z) = Z
by FDIFF_1:def 7;
then A7: dom (x (#) (y `| Z)) =
(dom x) /\ Z
by VALUED_1:def 4
.=
Z
by A4, XBOOLE_1:28
;
A9:
((1 / 2) (#) ((x (#) x) + ((y `| Z) (#) (y `| Z)))) | ['a,b'] is continuous
by A1, A3;
A10:
((x (#) x) + ((y `| Z) (#) (y `| Z))) | ['a,b'] is continuous
by A1, A3;
A11: dom ((x (#) x) + ((y `| Z) (#) (y `| Z))) =
(dom (x (#) x)) /\ (dom ((y `| Z) (#) (y `| Z)))
by VALUED_1:def 1
.=
((dom x) /\ (dom x)) /\ (dom ((y `| Z) (#) (y `| Z)))
by VALUED_1:def 4
.=
(dom x) /\ (Z /\ Z)
by A6, VALUED_1:def 4
.=
Z
by A4, XBOOLE_1:28
;
then A12:
dom ((1 / 2) (#) ((x (#) x) + ((y `| Z) (#) (y `| Z)))) = Z
by VALUED_1:def 5;
set f = x (#) (y `| Z);
set g0 = (x (#) x) + ((y `| Z) (#) (y `| Z));
set g = (1 / 2) (#) ((x (#) x) + ((y `| Z) (#) (y `| Z)));
A13:
( (x (#) (y `| Z)) | ['a,b'] is bounded & x (#) (y `| Z) is_integrable_on ['a,b'] )
by A4, A5, A7, INTEGRA5:10, INTEGRA5:11;
A14:
( ((1 / 2) (#) ((x (#) x) + ((y `| Z) (#) (y `| Z)))) | ['a,b'] is bounded & (1 / 2) (#) ((x (#) x) + ((y `| Z) (#) (y `| Z))) is_integrable_on ['a,b'] )
by A4, A9, A12, INTEGRA5:10, INTEGRA5:11;
A15:
( ((x (#) x) + ((y `| Z) (#) (y `| Z))) | ['a,b'] is bounded & (x (#) x) + ((y `| Z) (#) (y `| Z)) is_integrable_on ['a,b'] )
by A4, A10, A11, INTEGRA5:10, INTEGRA5:11;
for t being Real st t in ['a,b'] holds
(x (#) (y `| Z)) . t <= ((1 / 2) (#) ((x (#) x) + ((y `| Z) (#) (y `| Z)))) . t
then
integral ((x (#) (y `| Z)),a,b) <= integral (((1 / 2) (#) ((x (#) x) + ((y `| Z) (#) (y `| Z)))),a,b)
by A4, A7, A12, A13, A14, ORDEQ_01:48;
hence
integral ((x (#) (y `| Z)),a,b) <= (1 / 2) * (integral (((x (#) x) + ((y `| Z) (#) (y `| Z))),a,b))
by A4, A11, A15, INTEGRA6:10; verum