let P, Q be pcs-Str ; for p, q being Element of (P --> Q)
for p1, p2 being Element of P
for q1, q2 being Element of Q st p = [p1,q1] & q = [p2,q2] & p (--) q & p1 (--) p2 holds
q1 (--) q2
let p, q be Element of (P --> Q); for p1, p2 being Element of P
for q1, q2 being Element of Q st p = [p1,q1] & q = [p2,q2] & p (--) q & p1 (--) p2 holds
q1 (--) q2
let p1, p2 be Element of P; for q1, q2 being Element of Q st p = [p1,q1] & q = [p2,q2] & p (--) q & p1 (--) p2 holds
q1 (--) q2
let q1, q2 be Element of Q; ( p = [p1,q1] & q = [p2,q2] & p (--) q & p1 (--) p2 implies q1 (--) q2 )
assume that
A1:
p = [p1,q1]
and
A2:
q = [p2,q2]
; ( not p (--) q or not p1 (--) p2 or q1 (--) q2 )
reconsider r1 = p1, r2 = p2 as Element of (pcs-reverse P) by Def40;
assume
[p,q] in the ToleranceRel of (P --> Q)
; PCS_0:def 7 ( not p1 (--) p2 or q1 (--) q2 )
then consider a, b, s, t being set such that
A3:
p = [a,b]
and
A4:
q = [s,t]
and
a in the carrier of (pcs-reverse P)
and
b in the carrier of Q
and
s in the carrier of (pcs-reverse P)
and
t in the carrier of Q
and
A5:
( [a,s] in the ToleranceRel of (pcs-reverse P) or [b,t] in the ToleranceRel of Q )
by Def2;
A6:
a = p1
by A1, A3, XTUPLE_0:1;
A7:
b = q1
by A1, A3, XTUPLE_0:1;
A8:
s = p2
by A2, A4, XTUPLE_0:1;
t = q2
by A2, A4, XTUPLE_0:1;
then
( r1 (--) r2 or q1 (--) q2 )
by A5, A6, A7, A8;
hence
( not p1 (--) p2 or q1 (--) q2 )
by Th34; verum