let N be invertible Matrix of 3,F_Real; for NR, M1, M2 being Matrix of 3,REAL
for a, b, c, d, e, f being Real st NR = MXF2MXR N & M1 = symmetric_3 (a,b,c,(d / 2),(f / 2),(e / 2)) & M2 = ((MXF2MXR ((MXR2MXF (NR @)) ~)) * M1) * (MXF2MXR ((MXR2MXF NR) ~)) holds
MXR2MXF M2 is symmetric
let NR, M1, M2 be Matrix of 3,REAL; for a, b, c, d, e, f being Real st NR = MXF2MXR N & M1 = symmetric_3 (a,b,c,(d / 2),(f / 2),(e / 2)) & M2 = ((MXF2MXR ((MXR2MXF (NR @)) ~)) * M1) * (MXF2MXR ((MXR2MXF NR) ~)) holds
MXR2MXF M2 is symmetric
let a, b, c, d, e, f be Real; ( NR = MXF2MXR N & M1 = symmetric_3 (a,b,c,(d / 2),(f / 2),(e / 2)) & M2 = ((MXF2MXR ((MXR2MXF (NR @)) ~)) * M1) * (MXF2MXR ((MXR2MXF NR) ~)) implies MXR2MXF M2 is symmetric )
assume A1:
( NR = MXF2MXR N & M1 = symmetric_3 (a,b,c,(d / 2),(f / 2),(e / 2)) & M2 = ((MXF2MXR ((MXR2MXF (NR @)) ~)) * M1) * (MXF2MXR ((MXR2MXF NR) ~)) )
; MXR2MXF M2 is symmetric
reconsider M = symmetric_3 (a,b,c,(d / 2),(f / 2),(e / 2)) as Matrix of 3,REAL ;
A2:
MXR2MXF M = symmetric_3 (a,b,c,(d / 2),(f / 2),(e / 2))
by MATRIXR1:def 1;
reconsider Q = (MXR2MXF (NR @)) ~ as Matrix of 3,F_Real ;
reconsider T = MXF2MXR ((MXR2MXF (NR @)) ~) as Matrix of 3,REAL by MATRIXR1:def 2;
T * M is Matrix of 3,REAL
;
then reconsider M3 = (MXF2MXR ((MXR2MXF (NR @)) ~)) * M, M4 = MXF2MXR ((MXR2MXF NR) ~) as Matrix of 3,REAL by MATRIXR1:def 2;
reconsider M5 = (MXR2MXF (NR @)) ~ as Matrix of 3,F_Real ;
reconsider M6 = MXF2MXR M5 as Matrix of 3,REAL by MATRIXR1:def 2;
NR @ is invertible
by A1, Lm12;
then A3:
MXR2MXF (NR @) is invertible
by Lm15;
A4:
(MXR2MXF (NR @)) @ = MXR2MXF NR
A7:
M5 @ = (MXR2MXF NR) ~
by A3, MATRIX14:31, A4;
MXR2MXF M2 is symmetric
hence
MXR2MXF M2 is symmetric
; verum