let f, g be Function; for x, y, z being object st f tolerates g & [x,y] in f & [x,z] in g holds
y = z
let x, y, z be object ; ( f tolerates g & [x,y] in f & [x,z] in g implies y = z )
set h = f \/ g;
assume
f tolerates g
; ( not [x,y] in f or not [x,z] in g or y = z )
then A1:
f \/ g is Function
by Th51;
assume
( [x,y] in f & [x,z] in g )
; y = z
then
( [x,y] in f \/ g & [x,z] in f \/ g )
by XBOOLE_0:def 3;
hence
y = z
by A1, FUNCT_1:def 1; verum