let a, b, c be Ordinal; ( 0 in c & c in b implies b -exponent (c *^ (exp (b,a))) = a )
assume A1:
( 0 in c & c in b )
; b -exponent (c *^ (exp (b,a))) = a
then A2:
succ 0 c= c
by ORDINAL1:21;
then A3:
( 1 *^ (exp (b,a)) = exp (b,a) & 1 *^ (exp (b,a)) c= c *^ (exp (b,a)) )
by ORDINAL2:39, ORDINAL2:41;
A4:
( 1 in b & 0 in c *^ (exp (b,a)) )
by A2, A1, ORDINAL1:12, ORDINAL3:8;
now for d being Ordinal st exp (b,d) c= c *^ (exp (b,a)) holds
not d c/= alet d be
Ordinal;
( exp (b,d) c= c *^ (exp (b,a)) implies not d c/= a )assume A5:
(
exp (
b,
d)
c= c *^ (exp (b,a)) &
d c/= a )
;
contradictionthen
succ a c= d
by ORDINAL1:16, ORDINAL1:21;
then A6:
exp (
b,
(succ a))
c= exp (
b,
d)
by A1, ORDINAL4:27;
exp (
b,
(succ a))
= b *^ (exp (b,a))
by ORDINAL2:44;
then
b *^ (exp (b,a)) c= c *^ (exp (b,a))
by A5, A6;
then
b c= c
by ORDINAL3:35;
then
c in c
by A1;
hence
contradiction
;
verum end;
hence
b -exponent (c *^ (exp (b,a))) = a
by A3, A4, Def10; verum