let R be Relation; for X being set st R partially_orders X & field R = X & X has_upper_Zorn_property_wrt R holds
ex x being set st x is_maximal_in R
let FIELD be set ; ( R partially_orders FIELD & field R = FIELD & FIELD has_upper_Zorn_property_wrt R implies ex x being set st x is_maximal_in R )
assume that
A1:
R is_reflexive_in FIELD
and
A2:
R is_transitive_in FIELD
and
A3:
R is_antisymmetric_in FIELD
and
A4:
field R = FIELD
and
A5:
FIELD has_upper_Zorn_property_wrt R
; ORDERS_1:def 8 ex x being set st x is_maximal_in R
reconsider XD = FIELD as non empty set by A5, Th49;
consider D being non empty set such that
A6:
D = XD
;
A7:
D in bool D
by ZFMISC_1:def 1;
not D in {{}}
by TARSKI:def 1;
then reconsider M = (bool D) \ {{}} as non empty set by A7, XBOOLE_0:def 5;
set f = the Choice_Function of M;
defpred S1[ object , object ] means ( ( $1 <> {} & $2 = the Choice_Function of M . $1 ) or ( $1 = {} & $2 = D ) );
A8:
for x being object st x in bool D holds
ex y being object st S1[x,y]
A9:
for x, y, z being object st x in bool D & S1[x,y] & S1[x,z] holds
y = z
;
consider g being Function such that
A10:
( dom g = bool D & ( for x being object st x in bool D holds
S1[x,g . x] ) )
from FUNCT_1:sch 2(A9, A8);
defpred S2[ Ordinal, object ] means ex L being Sequence st
( $2 = g . { d where d is Element of D : for x being set st x in rng L holds
( x <> d & [x,d] in R ) } & dom L = $1 & ( for A being Ordinal
for L1 being Sequence st A in $1 & L1 = L | A holds
L . A = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } ) );
A11:
for x, y being set
for A being Ordinal st S2[A,x] & S2[A,y] holds
x = y
proof
let x,
y be
set ;
for A being Ordinal st S2[A,x] & S2[A,y] holds
x = ylet A be
Ordinal;
( S2[A,x] & S2[A,y] implies x = y )
given L1 being
Sequence such that A12:
x = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) }
and A13:
(
dom L1 = A & ( for
C being
Ordinal for
L being
Sequence st
C in A &
L = L1 | C holds
L1 . C = g . { d2 where d2 is Element of D : for x being set st x in rng L holds
( x <> d2 & [x,d2] in R ) } ) )
;
( not S2[A,y] or x = y )
A14:
L1 = L1 | A
by A13;
given L2 being
Sequence such that A15:
y = g . { d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) }
and A16:
(
dom L2 = A & ( for
C being
Ordinal for
L being
Sequence st
C in A &
L = L2 | C holds
L2 . C = g . { d2 where d2 is Element of D : for x being set st x in rng L holds
( x <> d2 & [x,d2] in R ) } ) )
;
x = y
defpred S3[
Ordinal]
means ( $1
c= A implies
L1 | $1
= L2 | $1 );
A17:
for
A1 being
Ordinal st ( for
A2 being
Ordinal st
A2 in A1 holds
S3[
A2] ) holds
S3[
A1]
proof
let A1 be
Ordinal;
( ( for A2 being Ordinal st A2 in A1 holds
S3[A2] ) implies S3[A1] )
assume that A18:
for
A2 being
Ordinal st
A2 in A1 &
A2 c= A holds
L1 | A2 = L2 | A2
and A19:
A1 c= A
;
L1 | A1 = L2 | A1
A20:
dom (L2 | A1) = A1
by A16, A19, RELAT_1:62;
A21:
now for x being object st x in A1 holds
(L1 | A1) . x = (L2 | A1) . xlet x be
object ;
( x in A1 implies (L1 | A1) . x = (L2 | A1) . x )assume A22:
x in A1
;
(L1 | A1) . x = (L2 | A1) . xthen reconsider A3 =
x as
Ordinal ;
A23:
L1 . x = (L1 | A1) . x
by A22, FUNCT_1:49;
A3 c= A
by A19, A22, ORDINAL1:def 2;
then A24:
L1 | A3 = L2 | A3
by A18, A22;
A25:
L2 . A3 = g . { d2 where d2 is Element of D : for x being set st x in rng (L2 | A3) holds
( x <> d2 & [x,d2] in R ) }
by A16, A19, A22;
L1 . A3 = g . { d1 where d1 is Element of D : for x being set st x in rng (L1 | A3) holds
( x <> d1 & [x,d1] in R ) }
by A13, A19, A22;
hence
(L1 | A1) . x = (L2 | A1) . x
by A22, A24, A23, A25, FUNCT_1:49;
verum end;
dom (L1 | A1) = A1
by A13, A19, RELAT_1:62;
hence
L1 | A1 = L2 | A1
by A20, A21, FUNCT_1:2;
verum
end;
for
A1 being
Ordinal holds
S3[
A1]
from ORDINAL1:sch 2(A17);
then A26:
L1 | A = L2 | A
;
L2 = L2 | A
by A16;
hence
x = y
by A12, A15, A26, A14;
verum
end;
{} in {{}}
by TARSKI:def 1;
then A27:
not {} in M
by XBOOLE_0:def 5;
A28:
for X being set st X in bool D & X <> {} holds
g . X in X
defpred S3[ Ordinal] means S2[$1,D];
{} c= D
;
then A32:
g . {} = D
by A10;
A33:
now for A, B being Ordinal
for L1, L2 being Sequence st dom L1 = A & ( for C being Ordinal
for L being Sequence st C in A & L = L1 | C holds
L1 . C = g . { d2 where d2 is Element of D : for x being set st x in rng L holds
( x <> d2 & [x,d2] in R ) } ) & dom L2 = B & ( for C being Ordinal
for L being Sequence st C in B & L = L2 | C holds
L2 . C = g . { d2 where d2 is Element of D : for x being set st x in rng L holds
( x <> d2 & [x,d2] in R ) } ) holds
for C being Ordinal st C c= A & C c= B holds
L1 | C = L2 | Clet A,
B be
Ordinal;
for L1, L2 being Sequence st dom L1 = A & ( for C being Ordinal
for L being Sequence st C in A & L = L1 | C holds
L1 . C = g . { d2 where d2 is Element of D : for x being set st x in rng L holds
( x <> d2 & [x,d2] in R ) } ) & dom L2 = B & ( for C being Ordinal
for L being Sequence st C in B & L = L2 | C holds
L2 . C = g . { d2 where d2 is Element of D : for x being set st x in rng L holds
( x <> d2 & [x,d2] in R ) } ) holds
for C being Ordinal st C c= A & C c= B holds
L1 | C = L2 | Clet L1,
L2 be
Sequence;
( dom L1 = A & ( for C being Ordinal
for L being Sequence st C in A & L = L1 | C holds
L1 . C = g . { d2 where d2 is Element of D : for x being set st x in rng L holds
( x <> d2 & [x,d2] in R ) } ) & dom L2 = B & ( for C being Ordinal
for L being Sequence st C in B & L = L2 | C holds
L2 . C = g . { d2 where d2 is Element of D : for x being set st x in rng L holds
( x <> d2 & [x,d2] in R ) } ) implies for C being Ordinal st C c= A & C c= B holds
L1 | C = L2 | C )assume that A34:
(
dom L1 = A & ( for
C being
Ordinal for
L being
Sequence st
C in A &
L = L1 | C holds
L1 . C = g . { d2 where d2 is Element of D : for x being set st x in rng L holds
( x <> d2 & [x,d2] in R ) } ) )
and A35:
(
dom L2 = B & ( for
C being
Ordinal for
L being
Sequence st
C in B &
L = L2 | C holds
L2 . C = g . { d2 where d2 is Element of D : for x being set st x in rng L holds
( x <> d2 & [x,d2] in R ) } ) )
;
for C being Ordinal st C c= A & C c= B holds
L1 | C = L2 | Clet C be
Ordinal;
( C c= A & C c= B implies L1 | C = L2 | C )assume that A36:
C c= A
and A37:
C c= B
;
L1 | C = L2 | Cdefpred S4[
Ordinal]
means ( $1
c= C implies
L1 | $1
= L2 | $1 );
A38:
for
A1 being
Ordinal st ( for
A2 being
Ordinal st
A2 in A1 holds
S4[
A2] ) holds
S4[
A1]
proof
let A1 be
Ordinal;
( ( for A2 being Ordinal st A2 in A1 holds
S4[A2] ) implies S4[A1] )
assume that A39:
for
A2 being
Ordinal st
A2 in A1 &
A2 c= C holds
L1 | A2 = L2 | A2
and A40:
A1 c= C
;
L1 | A1 = L2 | A1
A41:
dom (L2 | A1) = A1
by A35, A37, A40, RELAT_1:62, XBOOLE_1:1;
A42:
now for x being object st x in A1 holds
(L1 | A1) . x = (L2 | A1) . xlet x be
object ;
( x in A1 implies (L1 | A1) . x = (L2 | A1) . x )assume A43:
x in A1
;
(L1 | A1) . x = (L2 | A1) . xthen reconsider A3 =
x as
Ordinal ;
A44:
L1 . x = (L1 | A1) . x
by A43, FUNCT_1:49;
A3 c= C
by A40, A43, ORDINAL1:def 2;
then A45:
L1 | A3 = L2 | A3
by A39, A43;
A46:
A3 in C
by A40, A43;
then A47:
L2 . A3 = g . { d2 where d2 is Element of D : for x being set st x in rng (L2 | A3) holds
( x <> d2 & [x,d2] in R ) }
by A35, A37;
L1 . A3 = g . { d1 where d1 is Element of D : for x being set st x in rng (L1 | A3) holds
( x <> d1 & [x,d1] in R ) }
by A34, A36, A46;
hence
(L1 | A1) . x = (L2 | A1) . x
by A43, A45, A44, A47, FUNCT_1:49;
verum end;
dom (L1 | A1) = A1
by A34, A36, A40, RELAT_1:62, XBOOLE_1:1;
hence
L1 | A1 = L2 | A1
by A41, A42, FUNCT_1:2;
verum
end;
for
A1 being
Ordinal holds
S4[
A1]
from ORDINAL1:sch 2(A38);
hence
L1 | C = L2 | C
;
verum end;
A48:
for d being Element of D
for A, B being Ordinal st S2[A,d] & S2[B,d] holds
A = B
proof
let d be
Element of
D;
for A, B being Ordinal st S2[A,d] & S2[B,d] holds
A = Blet A,
B be
Ordinal;
( S2[A,d] & S2[B,d] implies A = B )
given L1 being
Sequence such that A49:
d = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) }
and A50:
(
dom L1 = A & ( for
C being
Ordinal for
L being
Sequence st
C in A &
L = L1 | C holds
L1 . C = g . { d2 where d2 is Element of D : for x being set st x in rng L holds
( x <> d2 & [x,d2] in R ) } ) )
;
( not S2[B,d] or A = B )
given L2 being
Sequence such that A51:
d = g . { d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) }
and A52:
(
dom L2 = B & ( for
C being
Ordinal for
L being
Sequence st
C in B &
L = L2 | C holds
L2 . C = g . { d2 where d2 is Element of D : for x being set st x in rng L holds
( x <> d2 & [x,d2] in R ) } ) )
;
A = B
A53:
now not B in Aset Y =
{ d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } ;
set X =
{ d1 where d1 is Element of D : for x being set st x in rng (L1 | B) holds
( x <> d1 & [x,d1] in R ) } ;
A54:
{ d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } c= D
assume A55:
B in A
;
contradictionthen
B c= A
by ORDINAL1:def 2;
then A56:
L1 | B =
L2 | B
by A33, A50, A52
.=
L2
by A52
;
L1 . B = g . { d1 where d1 is Element of D : for x being set st x in rng (L1 | B) holds
( x <> d1 & [x,d1] in R ) }
by A50, A55;
then A57:
d in rng L1
by A50, A51, A55, A56, FUNCT_1:def 3;
A58:
now not { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } <> {} assume A59:
{ d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } <> {}
;
contradictionthen
not
{ d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } in {{}}
by TARSKI:def 1;
then A60:
{ d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } in M
by A54, XBOOLE_0:def 5;
g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } = the
Choice_Function of
M . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) }
by A10, A54, A59;
then
d in { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) }
by A27, A49, A60, Lm2;
then
ex
d1 being
Element of
D st
(
d = d1 & ( for
x being
set st
x in rng L1 holds
(
x <> d1 &
[x,d1] in R ) ) )
;
hence
contradiction
by A57;
verum end; A61:
not
d in d
;
S1[
{ d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } ,
g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } ]
by A10, A54;
hence
contradiction
by A49, A61, A58;
verum end;
now not A in Bset Y =
{ d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) } ;
set X =
{ d1 where d1 is Element of D : for x being set st x in rng (L2 | A) holds
( x <> d1 & [x,d1] in R ) } ;
A62:
{ d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) } c= D
assume A63:
A in B
;
contradictionthen
A c= B
by ORDINAL1:def 2;
then A64:
L2 | A =
L1 | A
by A33, A50, A52
.=
L1
by A50
;
L2 . A = g . { d1 where d1 is Element of D : for x being set st x in rng (L2 | A) holds
( x <> d1 & [x,d1] in R ) }
by A52, A63;
then A65:
d in rng L2
by A49, A52, A63, A64, FUNCT_1:def 3;
A66:
now not { d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) } <> {} assume A67:
{ d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) } <> {}
;
contradictionthen
not
{ d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) } in {{}}
by TARSKI:def 1;
then A68:
{ d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) } in M
by A62, XBOOLE_0:def 5;
g . { d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) } = the
Choice_Function of
M . { d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) }
by A10, A62, A67;
then
d in { d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) }
by A27, A51, A68, Lm2;
then
ex
d1 being
Element of
D st
(
d = d1 & ( for
x being
set st
x in rng L2 holds
(
x <> d1 &
[x,d1] in R ) ) )
;
hence
contradiction
by A65;
verum end; A69:
not
d in d
;
S1[
{ d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) } ,
g . { d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) } ]
by A10, A62;
hence
contradiction
by A51, A69, A66;
verum end;
hence
A = B
by A53, ORDINAL1:14;
verum
end;
A70:
ex A1 being Ordinal st S3[A1]
proof
defpred S4[
object ,
object ]
means ex
A being
Ordinal st
( $2
= A &
S2[
A,$1] );
defpred S5[
Ordinal]
means ex
d being
Element of
D st
S2[$1,
d];
assume A71:
for
A1 being
Ordinal holds not
S2[
A1,
D]
;
contradiction
A72:
for
A being
Ordinal st ( for
B being
Ordinal st
B in A holds
S5[
B] ) holds
S5[
A]
proof
defpred S6[
object ,
object ]
means ex
C being
Ordinal st
( $1
= C &
S2[
C,$2] );
let A be
Ordinal;
( ( for B being Ordinal st B in A holds
S5[B] ) implies S5[A] )
assume A73:
for
B being
Ordinal st
B in A holds
ex
d being
Element of
D st
S2[
B,
d]
;
S5[A]
A74:
for
x being
object st
x in A holds
ex
y being
object st
S6[
x,
y]
proof
let x be
object ;
( x in A implies ex y being object st S6[x,y] )
assume A75:
x in A
;
ex y being object st S6[x,y]
then reconsider C =
x as
Ordinal ;
consider d being
Element of
D such that A76:
S2[
C,
d]
by A73, A75;
reconsider y =
d as
set ;
take
y
;
S6[x,y]
take
C
;
( x = C & S2[C,y] )
thus
(
x = C &
S2[
C,
y] )
by A76;
verum
end;
A77:
for
x,
y,
z being
object st
x in A &
S6[
x,
y] &
S6[
x,
z] holds
y = z
by A11;
consider h being
Function such that A78:
(
dom h = A & ( for
x being
object st
x in A holds
S6[
x,
h . x] ) )
from FUNCT_1:sch 2(A77, A74);
reconsider h =
h as
Sequence by A78, ORDINAL1:def 7;
set X =
{ d1 where d1 is Element of D : for x being set st x in rng h holds
( x <> d1 & [x,d1] in R ) } ;
A79:
{ d1 where d1 is Element of D : for x being set st x in rng h holds
( x <> d1 & [x,d1] in R ) } c= D
A80:
S2[
A,
g . { d1 where d1 is Element of D : for x being set st x in rng h holds
( x <> d1 & [x,d1] in R ) } ]
proof
take
h
;
( g . { d1 where d1 is Element of D : for x being set st x in rng h holds
( x <> d1 & [x,d1] in R ) } = g . { d where d is Element of D : for x being set st x in rng h holds
( x <> d & [x,d] in R ) } & dom h = A & ( for A being Ordinal
for L1 being Sequence st A in A & L1 = h | A holds
h . A = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } ) )
thus
(
g . { d1 where d1 is Element of D : for x being set st x in rng h holds
( x <> d1 & [x,d1] in R ) } = g . { d1 where d1 is Element of D : for x being set st x in rng h holds
( x <> d1 & [x,d1] in R ) } &
dom h = A )
by A78;
for A being Ordinal
for L1 being Sequence st A in A & L1 = h | A holds
h . A = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) }
let B be
Ordinal;
for L1 being Sequence st B in A & L1 = h | B holds
h . B = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } let L be
Sequence;
( B in A & L = h | B implies h . B = g . { d1 where d1 is Element of D : for x being set st x in rng L holds
( x <> d1 & [x,d1] in R ) } )
assume that A81:
B in A
and A82:
L = h | B
;
h . B = g . { d1 where d1 is Element of D : for x being set st x in rng L holds
( x <> d1 & [x,d1] in R ) }
ex
C being
Ordinal st
(
B = C &
S2[
C,
h . B] )
by A78, A81;
then consider L1 being
Sequence such that A83:
h . B = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) }
and A84:
(
dom L1 = B & ( for
C being
Ordinal for
L being
Sequence st
C in B &
L = L1 | C holds
L1 . C = g . { d1 where d1 is Element of D : for x being set st x in rng L holds
( x <> d1 & [x,d1] in R ) } ) )
;
A85:
for
x being
object st
x in B holds
L1 . x = (h | B) . x
proof
let x be
object ;
( x in B implies L1 . x = (h | B) . x )
assume A86:
x in B
;
L1 . x = (h | B) . x
then reconsider A1 =
x as
Ordinal ;
A87:
(h | B) . x = h . x
by A86, FUNCT_1:49;
A88:
S2[
A1,
L1 . x]
proof
reconsider K =
L1 | A1 as
Sequence ;
take
K
;
( L1 . x = g . { d where d is Element of D : for x being set st x in rng K holds
( x <> d & [x,d] in R ) } & dom K = A1 & ( for A being Ordinal
for L1 being Sequence st A in A1 & L1 = K | A holds
K . A = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } ) )
thus
L1 . x = g . { d1 where d1 is Element of D : for x being set st x in rng K holds
( x <> d1 & [x,d1] in R ) }
by A84, A86;
( dom K = A1 & ( for A being Ordinal
for L1 being Sequence st A in A1 & L1 = K | A holds
K . A = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } ) )
A1 c= B
by A86, ORDINAL1:def 2;
hence
dom K = A1
by A84, RELAT_1:62;
for A being Ordinal
for L1 being Sequence st A in A1 & L1 = K | A holds
K . A = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) }
let A2 be
Ordinal;
for L1 being Sequence st A2 in A1 & L1 = K | A2 holds
K . A2 = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } let L2 be
Sequence;
( A2 in A1 & L2 = K | A2 implies K . A2 = g . { d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) } )
assume that A89:
A2 in A1
and A90:
L2 = K | A2
;
K . A2 = g . { d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) }
A2 c= A1
by A89, ORDINAL1:def 2;
then A91:
L2 = L1 | A2
by A90, FUNCT_1:51;
K . A2 = L1 . A2
by A89, FUNCT_1:49;
hence
K . A2 = g . { d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) }
by A84, A86, A89, A91, ORDINAL1:10;
verum
end;
ex
A2 being
Ordinal st
(
x = A2 &
S2[
A2,
h . x] )
by A78, A81, A86, ORDINAL1:10;
hence
L1 . x = (h | B) . x
by A11, A88, A87;
verum
end;
B c= A
by A81, ORDINAL1:def 2;
then
dom (h | B) = B
by A78, RELAT_1:62;
then
h | B = L1
by A84, A85, FUNCT_1:2;
hence
h . B = g . { d1 where d1 is Element of D : for x being set st x in rng L holds
( x <> d1 & [x,d1] in R ) }
by A82, A83;
verum
end;
then
{ d1 where d1 is Element of D : for x being set st x in rng h holds
( x <> d1 & [x,d1] in R ) } <> {}
by A32, A71;
then
g . { d1 where d1 is Element of D : for x being set st x in rng h holds
( x <> d1 & [x,d1] in R ) } in { d1 where d1 is Element of D : for x being set st x in rng h holds
( x <> d1 & [x,d1] in R ) }
by A28, A79;
then reconsider dd =
g . { d1 where d1 is Element of D : for x being set st x in rng h holds
( x <> d1 & [x,d1] in R ) } as
Element of
D by A79;
take
dd
;
S2[A,dd]
thus
S2[
A,
dd]
by A80;
verum
end;
A92:
for
A being
Ordinal holds
S5[
A]
from ORDINAL1:sch 2(A72);
A93:
for
x,
y,
z being
object st
S4[
x,
y] &
S4[
x,
z] holds
y = z
proof
let x,
y,
z be
object ;
( S4[x,y] & S4[x,z] implies y = z )
given A1 being
Ordinal such that A94:
y = A1
and A95:
S2[
A1,
x]
;
( not S4[x,z] or y = z )
consider d1 being
Element of
D such that A96:
S2[
A1,
d1]
by A92;
given A2 being
Ordinal such that A97:
z = A2
and A98:
S2[
A2,
x]
;
y = z
d1 = x
by A11, A95, A96;
hence
y = z
by A48, A94, A95, A97, A98;
verum
end;
consider X being
set such that A99:
for
x being
object holds
(
x in X iff ex
y being
object st
(
y in D &
S4[
y,
x] ) )
from TARSKI:sch 1(A93);
for
A being
Ordinal holds
A in X
hence
contradiction
by ORDINAL1:26;
verum
end;
consider A being Ordinal such that
A100:
( S3[A] & ( for B being Ordinal st S3[B] holds
A c= B ) )
from ORDINAL1:sch 1(A70);
A101:
for L being Sequence holds { d where d is Element of D : for x being set st x in rng L holds
( x <> d & [x,d] in R ) } c= D
D in bool D
by ZFMISC_1:def 1;
then reconsider d = g . D as Element of D by A28;
A102:
( d in D & S2[ {} ,d] )
proof
deffunc H1(
set )
-> set =
{} ;
thus
d in D
;
S2[ {} ,d]
consider L being
Sequence such that A103:
(
dom L = {} & ( for
B being
Ordinal for
L1 being
Sequence st
B in {} &
L1 = L | B holds
L . B = H1(
L1) ) )
from ORDINAL1:sch 4();
take
L
;
( d = g . { d where d is Element of D : for x being set st x in rng L holds
( x <> d & [x,d] in R ) } & dom L = {} & ( for A being Ordinal
for L1 being Sequence st A in {} & L1 = L | A holds
L . A = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } ) )
A104:
D c= { d1 where d1 is Element of D : for x being set st x in rng L holds
( x <> d1 & [x,d1] in R ) }
{ d1 where d1 is Element of D : for x being set st x in rng L holds
( x <> d1 & [x,d1] in R ) } c= D
by A101;
hence
d = g . { d1 where d1 is Element of D : for x being set st x in rng L holds
( x <> d1 & [x,d1] in R ) }
by A104, XBOOLE_0:def 10;
( dom L = {} & ( for A being Ordinal
for L1 being Sequence st A in {} & L1 = L | A holds
L . A = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } ) )
thus
dom L = {}
by A103;
for A being Ordinal
for L1 being Sequence st A in {} & L1 = L | A holds
L . A = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) }
thus
for
A being
Ordinal for
L1 being
Sequence st
A in {} &
L1 = L | A holds
L . A = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) }
;
verum
end;
A105:
{} c= A
;
defpred S4[ object ] means ex B being Ordinal st
( B in A & S2[B,$1] );
consider X being set such that
A106:
for x being object holds
( x in X iff ( x in D & S4[x] ) )
from XBOOLE_0:sch 1();
for Y being set holds not Y in Y
;
then
d <> D
;
then
{} <> A
by A11, A100, A102;
then
{} c< A
by A105;
then
{} in A
by ORDINAL1:11;
then reconsider X = X as non empty set by A106, A102;
consider L being Sequence such that
A107:
D = g . { d1 where d1 is Element of D : for x being set st x in rng L holds
( x <> d1 & [x,d1] in R ) }
and
A108:
( dom L = A & ( for B being Ordinal
for L1 being Sequence st B in A & L1 = L | B holds
L . B = g . { d2 where d2 is Element of D : for x being set st x in rng L1 holds
( x <> d2 & [x,d2] in R ) } ) )
by A100;
R is transitive
by A2, A4;
then A109:
R |_2 X is transitive
by WELLORD1:17;
A110:
rng L c= X
proof
let z be
object ;
TARSKI:def 3 ( not z in rng L or z in X )
assume
z in rng L
;
z in X
then consider y being
object such that A111:
y in dom L
and A112:
z = L . y
by FUNCT_1:def 3;
reconsider y =
y as
Ordinal by A111;
set Z =
{ d2 where d2 is Element of D : for x being set st x in rng (L | y) holds
( x <> d2 & [x,d2] in R ) } ;
A113:
{ d2 where d2 is Element of D : for x being set st x in rng (L | y) holds
( x <> d2 & [x,d2] in R ) } c= D
by A101;
A114:
S2[
y,
z]
proof
reconsider K =
L | y as
Sequence ;
take
K
;
( z = g . { d where d is Element of D : for x being set st x in rng K holds
( x <> d & [x,d] in R ) } & dom K = y & ( for A being Ordinal
for L1 being Sequence st A in y & L1 = K | A holds
K . A = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } ) )
thus
z = g . { d2 where d2 is Element of D : for x being set st x in rng K holds
( x <> d2 & [x,d2] in R ) }
by A108, A111, A112;
( dom K = y & ( for A being Ordinal
for L1 being Sequence st A in y & L1 = K | A holds
K . A = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } ) )
y c= dom L
by A111, ORDINAL1:def 2;
hence A115:
dom K = y
by RELAT_1:62;
for A being Ordinal
for L1 being Sequence st A in y & L1 = K | A holds
K . A = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) }
let B be
Ordinal;
for L1 being Sequence st B in y & L1 = K | B holds
K . B = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } let L1 be
Sequence;
( B in y & L1 = K | B implies K . B = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } )
assume that A116:
B in y
and A117:
L1 = K | B
;
K . B = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) }
B c= y
by A116, ORDINAL1:def 2;
then A118:
L1 = L | B
by A117, FUNCT_1:51;
K . B = L . B
by A115, A116, FUNCT_1:47;
hence
K . B = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) }
by A108, A111, A116, A118, ORDINAL1:10;
verum
end;
then
g . { d2 where d2 is Element of D : for x being set st x in rng (L | y) holds
( x <> d2 & [x,d2] in R ) } in { d2 where d2 is Element of D : for x being set st x in rng (L | y) holds
( x <> d2 & [x,d2] in R ) }
by A28, A113;
then
z in { d2 where d2 is Element of D : for x being set st x in rng (L | y) holds
( x <> d2 & [x,d2] in R ) }
by A108, A111, A112;
hence
z in X
by A106, A108, A111, A114, A113;
verum
end;
A119:
R |_2 X is connected
proof
let x,
y be
object ;
RELAT_2:def 6,
RELAT_2:def 14 ( not x in field (R |_2 X) or not y in field (R |_2 X) or x = y or [x,y] in R |_2 X or [y,x] in R |_2 X )
assume that A120:
x in field (R |_2 X)
and A121:
y in field (R |_2 X)
;
( x = y or [x,y] in R |_2 X or [y,x] in R |_2 X )
A122:
x in X
by A120, WELLORD1:12;
then consider A1 being
Ordinal such that
A1 in A
and A123:
S2[
A1,
x]
by A106;
A124:
y in X
by A121, WELLORD1:12;
then consider A2 being
Ordinal such that
A2 in A
and A125:
S2[
A2,
y]
by A106;
reconsider x9 =
x,
y9 =
y as
Element of
D by A106, A122, A124;
consider L1 being
Sequence such that A126:
x9 = g . { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) }
and A127:
(
dom L1 = A1 & ( for
C being
Ordinal for
L being
Sequence st
C in A1 &
L = L1 | C holds
L1 . C = g . { d2 where d2 is Element of D : for x being set st x in rng L holds
( x <> d2 & [x,d2] in R ) } ) )
by A123;
consider L2 being
Sequence such that A128:
y9 = g . { d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) }
and A129:
(
dom L2 = A2 & ( for
C being
Ordinal for
L being
Sequence st
C in A2 &
L = L2 | C holds
L2 . C = g . { d2 where d2 is Element of D : for x being set st x in rng L holds
( x <> d2 & [x,d2] in R ) } ) )
by A125;
A130:
[x,y] in [:X,X:]
by A122, A124, ZFMISC_1:87;
A131:
now ( A1 in A2 & not x = y & not [x,y] in R |_2 X implies [y,x] in R |_2 X )set Y =
{ d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) } ;
set Z =
{ d1 where d1 is Element of D : for x being set st x in rng (L2 | A1) holds
( x <> d1 & [x,d1] in R ) } ;
not
y9 in y9
;
then A132:
{ d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) } <> {}
by A32, A128;
{ d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) } c= D
by A101;
then
y9 in { d1 where d1 is Element of D : for x being set st x in rng L2 holds
( x <> d1 & [x,d1] in R ) }
by A28, A128, A132;
then A133:
ex
d1 being
Element of
D st
(
y9 = d1 & ( for
x being
set st
x in rng L2 holds
(
x <> d1 &
[x,d1] in R ) ) )
;
assume A134:
A1 in A2
;
( x = y or [x,y] in R |_2 X or [y,x] in R |_2 X )then
A1 c= A2
by ORDINAL1:def 2;
then A135:
L2 | A1 =
L1 | A1
by A33, A127, A129
.=
L1
by A127
;
L2 . A1 = g . { d1 where d1 is Element of D : for x being set st x in rng (L2 | A1) holds
( x <> d1 & [x,d1] in R ) }
by A129, A134;
then
x9 in rng L2
by A126, A129, A134, A135, FUNCT_1:def 3;
then
[x,y] in R
by A133;
hence
(
x = y or
[x,y] in R |_2 X or
[y,x] in R |_2 X )
by A130, XBOOLE_0:def 4;
verum end;
A136:
[y,x] in [:X,X:]
by A122, A124, ZFMISC_1:87;
A137:
now ( A2 in A1 & not x = y & not [x,y] in R |_2 X implies [y,x] in R |_2 X )set Y =
{ d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } ;
set Z =
{ d1 where d1 is Element of D : for x being set st x in rng (L1 | A2) holds
( x <> d1 & [x,d1] in R ) } ;
for
d1 being
Element of
D holds not
d1 in d1
;
then A138:
{ d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } <> {}
by A32, A126;
{ d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) } c= D
by A101;
then
x9 in { d1 where d1 is Element of D : for x being set st x in rng L1 holds
( x <> d1 & [x,d1] in R ) }
by A28, A126, A138;
then A139:
ex
d1 being
Element of
D st
(
x9 = d1 & ( for
x being
set st
x in rng L1 holds
(
x <> d1 &
[x,d1] in R ) ) )
;
assume A140:
A2 in A1
;
( x = y or [x,y] in R |_2 X or [y,x] in R |_2 X )then
A2 c= A1
by ORDINAL1:def 2;
then A141:
L1 | A2 =
L2 | A2
by A33, A127, A129
.=
L2
by A129
;
L1 . A2 = g . { d1 where d1 is Element of D : for x being set st x in rng (L1 | A2) holds
( x <> d1 & [x,d1] in R ) }
by A127, A140;
then
y9 in rng L1
by A127, A128, A140, A141, FUNCT_1:def 3;
then
[y,x] in R
by A139;
hence
(
x = y or
[x,y] in R |_2 X or
[y,x] in R |_2 X )
by A136, XBOOLE_0:def 4;
verum end;
(
A1 = A2 & not
x = y & not
[x,y] in R |_2 X implies
[y,x] in R |_2 X )
by A11, A123, A125;
hence
(
x = y or
[x,y] in R |_2 X or
[y,x] in R |_2 X )
by A131, A137, ORDINAL1:14;
verum
end;
R is antisymmetric
by A3, A4;
then A142:
R |_2 X is antisymmetric
;
set Z = { d1 where d1 is Element of D : for x being set st x in rng L holds
( x <> d1 & [x,d1] in R ) } ;
A143:
X c= D
by A106;
R is reflexive
by A1, A4;
then
R |_2 X is reflexive
by WELLORD1:15;
then
R |_2 X is being_linear-order
by A109, A142, A119;
then consider x being set such that
A144:
x in D
and
A145:
for y being set st y in X holds
[y,x] in R
by A5, A6, A143;
take
x
; x is_maximal_in R
thus
x in field R
by A4, A6, A144; ORDERS_1:def 12 for y being set holds
( not y in field R or not y <> x or not [x,y] in R )
let y be set ; ( not y in field R or not y <> x or not [x,y] in R )
assume that
A146:
y in field R
and
A147:
y <> x
and
A148:
[x,y] in R
; contradiction
reconsider y9 = y as Element of D by A4, A6, A146;
now for z being set st z in rng L holds
( z <> y9 & [z,y] in R )let z be
set ;
( z in rng L implies ( z <> y9 & [z,y] in R ) )assume A150:
z in rng L
;
( z <> y9 & [z,y] in R )then reconsider z9 =
z as
Element of
X by A110;
thus
z <> y9
by A110, A149, A150;
[z,y] in RA151:
[z9,x] in R
by A145;
z in D
by A106, A110, A150;
hence
[z,y] in R
by A2, A4, A6, A144, A146, A148, A151;
verum end;
then A152:
y in { d1 where d1 is Element of D : for x being set st x in rng L holds
( x <> d1 & [x,d1] in R ) }
;
{ d1 where d1 is Element of D : for x being set st x in rng L holds
( x <> d1 & [x,d1] in R ) } c= D
by A101;
hence
contradiction
by A28, A107, A152, ORDINAL1:5; verum