let R be Relation; for x being set holds
( x is_inferior_of R ~ iff x is_superior_of R )
let x be set ; ( x is_inferior_of R ~ iff x is_superior_of R )
A1:
field R = field (R ~)
by RELAT_1:21;
thus
( x is_inferior_of R ~ implies x is_superior_of R )
( x is_superior_of R implies x is_inferior_of R ~ )proof
assume that A2:
x in field (R ~)
and A3:
for
y being
set st
y in field (R ~) &
y <> x holds
[x,y] in R ~
;
ORDERS_1:def 15 x is_superior_of R
thus
x in field R
by A2, RELAT_1:21;
ORDERS_1:def 14 for y being set st y in field R & y <> x holds
[y,x] in R
let y be
set ;
( y in field R & y <> x implies [y,x] in R )
assume that A4:
y in field R
and A5:
y <> x
;
[y,x] in R
[x,y] in R ~
by A1, A3, A4, A5;
hence
[y,x] in R
by RELAT_1:def 7;
verum
end;
assume that
A6:
x in field R
and
A7:
for y being set st y in field R & y <> x holds
[y,x] in R
; ORDERS_1:def 14 x is_inferior_of R ~
thus
x in field (R ~)
by A6, RELAT_1:21; ORDERS_1:def 15 for y being set st y in field (R ~) & y <> x holds
[x,y] in R ~
let y be set ; ( y in field (R ~) & y <> x implies [x,y] in R ~ )
assume that
A8:
y in field (R ~)
and
A9:
y <> x
; [x,y] in R ~
[y,x] in R
by A1, A7, A8, A9;
hence
[x,y] in R ~
by RELAT_1:def 7; verum