let n be Nat; ( ( n + 1 is prime implies primeNumbers (n,1) = {(n + 1)} ) & ( not n + 1 is prime implies primeNumbers (n,1) = {} ) )
assume A4:
not n + 1 is prime
; primeNumbers (n,1) = {}
assume
primeNumbers (n,1) <> {}
; contradiction
then consider y being object such that
A5:
y in primeNumbers (n,1)
by XBOOLE_0:def 1;
reconsider y = y as Nat by A5;
n < y
by A5, Th74;
then
( n + 1 <= y & y <= n + 1 )
by A5, Th74, NAT_1:13;
then
y = n + 1
by XXREAL_0:1;
hence
contradiction
by A4, A5, Th74; verum