let n, m, k be Nat; (primeNumbers (n,m)) \/ (primeNumbers ((n + m),k)) = primeNumbers (n,(m + k))
( primeNumbers (n,m) = (seq (n,m)) /\ SetPrimes & primeNumbers ((n + m),k) = (seq ((n + m),k)) /\ SetPrimes )
by NUMBER14:def 17;
hence (primeNumbers (n,m)) \/ (primeNumbers ((n + m),k)) =
((seq (n,m)) \/ (seq ((n + m),k))) /\ SetPrimes
by XBOOLE_1:23
.=
(seq (n,(m + k))) /\ SetPrimes
by Th77
.=
primeNumbers (n,(m + k))
by NUMBER14:def 17
;
verum