let X be infinite Subset of NAT; for a being Nat ex b being Nat st
( b > a & b in X )
let a be Nat; ex b being Nat st
( b > a & b in X )
assume
for b being Nat holds
( not b > a or not b in X )
; contradiction
then P1:
for b being Nat st b in X holds
b <= a
;
X c= (Seg a) \/ {0}
hence
contradiction
; verum