set t = H2(3);
<*H2(3),H2(3),H2(3),H2(3),H2(3),H2(3)*> " = <*(H2(3) "),(H2(3) "),(H2(3) "),(H2(3) "),(H2(3) "),(H2(3) ")*>
by Th17;
hence Sum (<*H2(3),H2(3),H2(3),H2(3),H2(3),H2(3)*> ") =
(((((H2(3) ") + (H2(3) ")) + (H2(3) ")) + (H2(3) ")) + (H2(3) ")) + (H2(3) ")
by Th22
.=
1
by NUMPOLY1:13
;
NUMBER17:def 6 verum