set f = <*2,3,6*>;
set g = <*(1 / 2),(1 / 3),(1 / 6)*>;
<*2,3,6*> " = <*(1 / 2),(1 / 3),(1 / 6)*>
proof
A1:
(
len (<*2,3,6*> ") = 3 &
len <*(1 / 2),(1 / 3),(1 / 6)*> = 3 )
by CARD_1:def 7;
hence
len (<*2,3,6*> ") = len <*(1 / 2),(1 / 3),(1 / 6)*>
;
FINSEQ_1:def 18 for b1 being set holds
( not 1 <= b1 or not b1 <= len (<*2,3,6*> ") or (<*2,3,6*> ") . b1 = <*(1 / 2),(1 / 3),(1 / 6)*> . b1 )
let k be
Nat;
( not 1 <= k or not k <= len (<*2,3,6*> ") or (<*2,3,6*> ") . k = <*(1 / 2),(1 / 3),(1 / 6)*> . k )
assume
( 1
<= k &
k <= len (<*2,3,6*> ") )
;
(<*2,3,6*> ") . k = <*(1 / 2),(1 / 3),(1 / 6)*> . k
then
not not
k = 1 & ... & not
k = 3
by A1;
hence <*(1 / 2),(1 / 3),(1 / 6)*> . k =
(<*2,3,6*> . k) "
.=
(<*2,3,6*> ") . k
by VALUED_1:10
;
verum
end;
hence Sum (<*2,3,6*> ") =
((1 / 2) + (1 / 3)) + (1 / 6)
by RVSUM_1:78
.=
1
;
NUMBER17:def 6 verum