let x, y be positive Nat; ( ((x * y) + x) + y = 2 |^ 32 iff ( ( x = 640 & y = 6700416 ) or ( x = 6700416 & y = 640 ) ) )
A1:
( x + 1 <> 0 + 1 & y + 1 <> 0 + 1 )
;
thus
( not ((x * y) + x) + y = 2 |^ 32 or ( x = 640 & y = 6700416 ) or ( x = 6700416 & y = 640 ) )
( ( ( x = 640 & y = 6700416 ) or ( x = 6700416 & y = 640 ) ) implies ((x * y) + x) + y = 2 |^ 32 )
thus
( ( ( x = 640 & y = 6700416 ) or ( x = 6700416 & y = 640 ) ) implies ((x * y) + x) + y = 2 |^ 32 )
by Lm11, Lm6, Lm12; verum