thus
for i, j being Nat st 0 < i & i <= 7 holds
ex k being Nat st (ArProg (j,i)) . k is Fibonacci
for k being Nat holds not (ArProg (4,8)) . k is Fibonacci proof
let i,
j be
Nat;
( 0 < i & i <= 7 implies ex k being Nat st (ArProg (j,i)) . k is Fibonacci )
assume A1:
(
0 < i &
i <= 7 )
;
ex k being Nat st (ArProg (j,i)) . k is Fibonacci
consider k being
Nat such that A2:
k > 0
and A3:
(
Fib 0,
Fib k are_congruent_mod i &
Fib 1,
Fib (k + 1) are_congruent_mod i )
by A1, Th10;
A4:
( 1
= 1
+ 0 &
k + 1
= (0 + k) + 1 &
0 + k = k )
;
consider f being
Nat such that A5:
(Fib f) mod i = j mod i
by A1, INT_1:58, Th9;
ex
w being
Nat st
f + (k * w) >= j
then consider w being
Nat such that A8:
f + (k * w) >= j
;
Fib ((f + (k * w)) + 2) >= f + (k * w)
by Th8;
then A9:
Fib ((f + (k * w)) + 2) >= j
by A8, XXREAL_0:2;
2
* k >= 2
* 1
by A2, NAT_1:14, XREAL_1:64;
then
(f + (k * w)) + (2 * k) >= (f + (k * w)) + 2
by XREAL_1:6;
then
Fib ((k * (2 + w)) + f) >= Fib ((f + (k * w)) + 2)
by FIB_NUM2:45;
then A10:
Fib ((k * (2 + w)) + f) >= j
by A9, XXREAL_0:2;
(k * (2 + w)) + f,
0 + f are_congruent_mod k
;
then
(Fib ((k * (2 + w)) + f)) mod i = j mod i
by A4, A3, Th11, A5, NAT_D:64;
then consider z being
Integer such that A11:
Fib ((k * (2 + w)) + f) = (z * i) + j
by A1, NAT_D:64, NAT_6:9;
z >= 0
by A1, A11, A10, XREAL_1:30;
then reconsider z =
z as
Element of
NAT by INT_1:3;
(ArProg (j,i)) . z = (z * i) + j
by NUMBER06:7;
hence
ex
k being
Nat st
(ArProg (j,i)) . k is
Fibonacci
by A11;
verum
end;
let k be Nat; not (ArProg (4,8)) . k is Fibonacci
( Fib 0, Fib (0 + 12) are_congruent_mod 8 & Fib (0 + 1), Fib ((0 + 12) + 1) are_congruent_mod 8 )
by Th13;
then A12:
for x, y being Nat st x,y are_congruent_mod 12 holds
Fib x, Fib y are_congruent_mod 8
by Th11;
for x being Nat st x < 12 holds
(Fib x) mod 8 <> 4
by Th13;
hence
not (ArProg (4,8)) . k is Fibonacci
by A12, Th12; verum