let s be Nat; :: thesis: for k, n being non zero Nat st k <> n & n <= s & k <= s holds
primenumber (k - 1) divides (sequenceA s) . n

let k, n be non zero Nat; :: thesis: ( k <> n & n <= s & k <= s implies primenumber (k - 1) divides (sequenceA s) . n )
assume that
A1: k <> n and
A2: n <= s and
A3: k <= s ; :: thesis: primenumber (k - 1) divides (sequenceA s) . n
reconsider s = s as non zero Nat by A2;
set A = sequenceA s;
set p = primenumber (k - 1);
set r = primenumber (n - 1);
set g = PrimeNumbersFS s;
A4: 0 + 1 <= k by NAT_1:13;
A5: len (PrimeNumbersFS s) = s by Th42;
then A6: k in dom (PrimeNumbersFS s) by A3, A4, FINSEQ_3:25;
A7: (PrimeNumbersFS s) . k = primenumber (k - 1) by A3, Th44;
n - 1 < s - 0 by A2, XREAL_1:8;
then reconsider e = (Product (PrimeNumbersFS s)) / (primenumber (n - 1)) as Nat by Th45;
set y = CRT (0,e,(- 1),(primenumber (n - 1)));
1 <= n by NAT_1:14;
then A8: n in dom (PrimeNumbersFS s) by A5, A2, FINSEQ_3:25;
A9: (sequenceA s) . n = (CRT (0,e,(- 1),(primenumber (n - 1)))) + (Product (PrimeNumbersFS s)) by A2, Def5;
A10: (PrimeNumbersFS s) . n = primenumber (n - 1) by A2, Th44;
then primenumber (n - 1),e are_coprime by A8, INT_6:25;
then CRT (0,e,(- 1),(primenumber (n - 1))) solves_CRT 0 ,e, - 1, primenumber (n - 1) by NUMBER14:def 2;
then A11: CRT (0,e,(- 1),(primenumber (n - 1))), 0 are_congruent_mod e ;
e divides Product (PrimeNumbersFS s) by NUMBER14:3;
then A12: e divides (CRT (0,e,(- 1),(primenumber (n - 1)))) + (Product (PrimeNumbersFS s)) by A11, NAT_D:8;
consider z being Integer such that
A13: z * ((PrimeNumbersFS s) . k) = (Product (PrimeNumbersFS s)) / ((PrimeNumbersFS s) . n) by A1, A6, INT_6:12;
(PrimeNumbersFS s) . k divides z * ((PrimeNumbersFS s) . k) ;
hence primenumber (k - 1) divides (sequenceA s) . n by A7, A9, A10, A12, A13, INT_2:9; :: thesis: verum