let k be Nat; for i, n, m, r being Integer st k <> i holds
divisors (n,m,k) misses divisors (n,m,i)
let i be Integer; for n, m, r being Integer st k <> i holds
divisors (n,m,k) misses divisors (n,m,i)
let n, m, r be Integer; ( k <> i implies divisors (n,m,k) misses divisors (n,m,i) )
assume A1:
k <> i
; divisors (n,m,k) misses divisors (n,m,i)
assume
divisors (n,m,k) meets divisors (n,m,i)
; contradiction
then consider x being object such that
A2:
( x in divisors (n,m,k) & x in divisors (n,m,i) )
by XBOOLE_0:3;
reconsider x = x as Nat by A2;
( x mod m = k & x mod m = i )
by A2, Th12;
hence
contradiction
by A1; verum