let x, y, z, t be positive Nat; ( x <= y & y <= z & z <= t implies ( (((1 / x) + (1 / y)) + (1 / z)) + (1 / t) = 1 iff ( ( x = 2 & y = 3 & z = 7 & t = 42 ) or ( x = 2 & y = 3 & z = 8 & t = 24 ) or ( x = 2 & y = 3 & z = 9 & t = 18 ) or ( x = 2 & y = 3 & z = 10 & t = 15 ) or ( x = 2 & y = 3 & z = 12 & t = 12 ) or ( x = 2 & y = 4 & z = 5 & t = 20 ) or ( x = 2 & y = 4 & z = 6 & t = 12 ) or ( x = 2 & y = 4 & z = 8 & t = 8 ) or ( x = 2 & y = 5 & z = 5 & t = 10 ) or ( x = 2 & y = 6 & z = 6 & t = 6 ) or ( x = 3 & y = 3 & z = 4 & t = 12 ) or ( x = 3 & y = 3 & z = 6 & t = 6 ) or ( x = 3 & y = 4 & z = 4 & t = 6 ) or ( x = 4 & y = 4 & z = 4 & t = 4 ) ) ) )
assume that
A1:
x <= y
and
A2:
y <= z
and
A3:
z <= t
; ( (((1 / x) + (1 / y)) + (1 / z)) + (1 / t) = 1 iff ( ( x = 2 & y = 3 & z = 7 & t = 42 ) or ( x = 2 & y = 3 & z = 8 & t = 24 ) or ( x = 2 & y = 3 & z = 9 & t = 18 ) or ( x = 2 & y = 3 & z = 10 & t = 15 ) or ( x = 2 & y = 3 & z = 12 & t = 12 ) or ( x = 2 & y = 4 & z = 5 & t = 20 ) or ( x = 2 & y = 4 & z = 6 & t = 12 ) or ( x = 2 & y = 4 & z = 8 & t = 8 ) or ( x = 2 & y = 5 & z = 5 & t = 10 ) or ( x = 2 & y = 6 & z = 6 & t = 6 ) or ( x = 3 & y = 3 & z = 4 & t = 12 ) or ( x = 3 & y = 3 & z = 6 & t = 6 ) or ( x = 3 & y = 4 & z = 4 & t = 6 ) or ( x = 4 & y = 4 & z = 4 & t = 4 ) ) )
thus
( not (((1 / x) + (1 / y)) + (1 / z)) + (1 / t) = 1 or ( x = 2 & y = 3 & z = 7 & t = 42 ) or ( x = 2 & y = 3 & z = 8 & t = 24 ) or ( x = 2 & y = 3 & z = 9 & t = 18 ) or ( x = 2 & y = 3 & z = 10 & t = 15 ) or ( x = 2 & y = 3 & z = 12 & t = 12 ) or ( x = 2 & y = 4 & z = 5 & t = 20 ) or ( x = 2 & y = 4 & z = 6 & t = 12 ) or ( x = 2 & y = 4 & z = 8 & t = 8 ) or ( x = 2 & y = 5 & z = 5 & t = 10 ) or ( x = 2 & y = 6 & z = 6 & t = 6 ) or ( x = 3 & y = 3 & z = 4 & t = 12 ) or ( x = 3 & y = 3 & z = 6 & t = 6 ) or ( x = 3 & y = 4 & z = 4 & t = 6 ) or ( x = 4 & y = 4 & z = 4 & t = 4 ) )
( ( ( x = 2 & y = 3 & z = 7 & t = 42 ) or ( x = 2 & y = 3 & z = 8 & t = 24 ) or ( x = 2 & y = 3 & z = 9 & t = 18 ) or ( x = 2 & y = 3 & z = 10 & t = 15 ) or ( x = 2 & y = 3 & z = 12 & t = 12 ) or ( x = 2 & y = 4 & z = 5 & t = 20 ) or ( x = 2 & y = 4 & z = 6 & t = 12 ) or ( x = 2 & y = 4 & z = 8 & t = 8 ) or ( x = 2 & y = 5 & z = 5 & t = 10 ) or ( x = 2 & y = 6 & z = 6 & t = 6 ) or ( x = 3 & y = 3 & z = 4 & t = 12 ) or ( x = 3 & y = 3 & z = 6 & t = 6 ) or ( x = 3 & y = 4 & z = 4 & t = 6 ) or ( x = 4 & y = 4 & z = 4 & t = 4 ) ) implies (((1 / x) + (1 / y)) + (1 / z)) + (1 / t) = 1 )proof
assume A4:
(((1 / x) + (1 / y)) + (1 / z)) + (1 / t) = 1
;
( ( x = 2 & y = 3 & z = 7 & t = 42 ) or ( x = 2 & y = 3 & z = 8 & t = 24 ) or ( x = 2 & y = 3 & z = 9 & t = 18 ) or ( x = 2 & y = 3 & z = 10 & t = 15 ) or ( x = 2 & y = 3 & z = 12 & t = 12 ) or ( x = 2 & y = 4 & z = 5 & t = 20 ) or ( x = 2 & y = 4 & z = 6 & t = 12 ) or ( x = 2 & y = 4 & z = 8 & t = 8 ) or ( x = 2 & y = 5 & z = 5 & t = 10 ) or ( x = 2 & y = 6 & z = 6 & t = 6 ) or ( x = 3 & y = 3 & z = 4 & t = 12 ) or ( x = 3 & y = 3 & z = 6 & t = 6 ) or ( x = 3 & y = 4 & z = 4 & t = 6 ) or ( x = 4 & y = 4 & z = 4 & t = 4 ) )
A5:
now not x < 2A6:
((1 / y) + (1 / z)) + (1 / t) > 0
;
assume
x < 2
;
contradictionthen
((((1 / 1) + (1 / y)) + (1 / z)) + (1 / t)) - 1
= 1
- 1
by A4, NAT_1:23;
hence
contradiction
by A6;
verum end;
A7:
now ( y > 4 implies ((1 / y) + (1 / z)) + (1 / t) <= (2 / 5) + (1 / 5) )end;
now ( ( x = 2 & ( ( y = 2 & contradiction ) or ( y = 3 & ( ( z = 7 & x = 2 & y = 3 & z = 7 & t = 42 ) or ( z = 8 & x = 2 & y = 3 & z = 8 & t = 24 ) or ( z = 9 & x = 2 & y = 3 & z = 9 & t = 18 ) or ( z = 10 & x = 2 & y = 3 & z = 10 & t = 15 ) or ( z = 11 & contradiction ) or ( z = 12 & x = 2 & y = 3 & z = 12 & t = 12 ) ) ) or ( y = 4 & ( ( z = 5 & x = 2 & y = 4 & z = 5 & t = 20 ) or ( z = 6 & x = 2 & y = 4 & z = 6 & t = 12 ) or ( z = 7 & contradiction ) or ( z = 8 & x = 2 & y = 4 & z = 8 & t = 8 ) ) ) or ( y = 5 & ( ( z = 5 & x = 2 & y = 5 & z = 5 & t = 10 ) or ( z = 6 & contradiction ) ) ) or ( y = 6 & x = 2 & y = 6 & z = 6 & t = 6 ) ) ) or ( x = 3 & ( ( y = 3 & ( ( z = 3 & contradiction ) or ( z = 4 & x = 3 & y = 3 & z = 4 & t = 12 ) or ( z = 5 & contradiction ) or ( z = 6 & x = 3 & y = 3 & z = 6 & t = 6 ) ) ) or ( y = 4 & x = 3 & y = 4 & z = 4 & t = 6 ) ) ) or ( x = 4 & x = 4 & y = 4 & z = 4 & t = 4 ) )A12:
not
((2 * 7) + 1) / 2 is
integer
by NUMBER05:37;
A13:
(1 / z) + 0 < (1 / z) + (1 / t)
by XREAL_1:8;
then
not not
x = 0 & ... & not
x = 4
;
per cases then
( x = 2 or x = 3 or x = 4 )
by A5;
case A15:
x = 2
;
verumthen A16:
((((1 / 2) + (1 / y)) + (1 / z)) + (1 / t)) - (1 / 2) = 1
- (1 / 2)
by A4;
then A17:
((1 / y) + (1 / z)) + (1 / t) = 1
/ 2
;
1
/ z <= 1
/ y
by A2, XREAL_1:118;
then A18:
(1 / y) + (1 / z) <= (1 / y) + (1 / y)
by XREAL_1:7;
1
/ t <= 1
/ z
by A3, XREAL_1:118;
then A19:
(1 / z) + (1 / t) <= (1 / z) + (1 / z)
by XREAL_1:7;
y <= t
by A2, A3, XXREAL_0:2;
then
1
/ t <= 1
/ y
by XREAL_1:118;
then
((1 / y) + (1 / z)) + (1 / t) <= ((1 / y) + (1 / y)) + (1 / y)
by A18, XREAL_1:7;
then
(1 / 2) * y <= (3 / y) * y
by A16, XREAL_1:64;
then
(1 / 2) * y <= 3
by XCMPLX_1:87;
then
((1 / 2) * y) * 2
<= 3
* 2
by XREAL_1:64;
then
not not
y = 0 & ... & not
y = 6
;
per cases then
( y = 2 or y = 3 or y = 4 or y = 5 or y = 6 )
by A1, A15;
case
y = 2
;
contradictionthen A20:
((1 / 2) + (1 / z)) + (1 / t) = 1
/ 2
by A17;
(1 / z) + (1 / t) > 0
;
hence
contradiction
by A20;
verum end; case A21:
y = 3
;
verumend; case A28:
y = 4
;
verumend; case A34:
y = 5
;
verumend; case A38:
y = 6
;
( x = 2 & y = 6 & z = 6 & t = 6 )then A39:
((1 / 6) + (1 / z)) + (1 / t) = 1
/ 2
by A16;
then A40:
(1 / z) + (1 / t) = 1
/ 3
;
(1 / 3) " >= (2 / z) "
by A19, A39, XREAL_1:85;
then
3
/ 1
>= z / 2
by XCMPLX_1:213;
then A41:
3
* 2
>= (z / 2) * 2
by XREAL_1:64;
then
(1 / 6) + (1 / t) = 1
/ 3
by A2, A40, A38, XXREAL_0:1;
hence
(
x = 2 &
y = 6 &
z = 6 &
t = 6 )
by A2, A15, A38, A41, XCMPLX_1:59, XXREAL_0:1;
verum end; end; end; case A42:
x = 3
;
verumthen A43:
((((1 / 3) + (1 / y)) + (1 / z)) + (1 / t)) - (1 / 3) = 1
- (1 / 3)
by A4;
then
not not
y = 0 & ... & not
y = 4
by A7;
per cases then
( y = 3 or y = 4 )
by A1, A42;
case A44:
y = 3
;
verumthen A45:
(((1 / 3) + (1 / z)) + (1 / t)) - (1 / 3) = (2 / 3) - (1 / 3)
by A43;
then A46:
(1 / z) + (1 / t) = 1
/ 3
;
then
not not
z = 0 & ... & not
z = 6
;
per cases then
( z = 3 or z = 4 or z = 5 or z = 6 )
by A2, A44;
case
z = 3
;
contradictionthen A49:
(1 / 3) + (1 / t) = 1
/ 3
by A46;
1
/ t > 0
;
hence
contradiction
by A49;
verum end; case A50:
z = 4
;
( x = 3 & y = 3 & z = 4 & t = 12 )end; case
z = 5
;
contradictionthen
(1 / 5) + (1 / t) = 1
/ 3
by A45;
then
(1 / t) " = (2 / 15) "
;
hence
contradiction
by A12;
verum end; case A51:
z = 6
;
( x = 3 & y = 3 & z = 6 & t = 6 )end; end; end; case A52:
y = 4
;
( x = 3 & y = 4 & z = 4 & t = 6 )then
(((1 / 4) + (1 / z)) + (1 / t)) - (1 / 4) = (2 / 3) - (1 / 4)
by A43;
then A53:
(1 / z) + (1 / t) = 5
/ 12
;
1
/ t <= 1
/ z
by A3, XREAL_1:118;
then
(1 / z) + (1 / t) <= (1 / z) + (1 / z)
by XREAL_1:7;
then
(1 / z) + (1 / t) <= 2
/ z
;
then
5
* z <= 2
* 12
by A53, XREAL_1:106;
then
(5 * z) / 5
<= (2 * 12) / 5
by XREAL_1:72;
then
z < 4
+ 1
by XXREAL_0:2;
then A54:
z <= 4
by NAT_1:13;
then
((1 / 4) + (1 / t)) - (1 / 4) = (5 / 12) - (1 / 4)
by A53, A2, A52, XXREAL_0:1;
then
1
/ t = 1
/ 6
;
hence
(
x = 3 &
y = 4 &
z = 4 &
t = 6 )
by A42, A54, A2, A52, XXREAL_0:1, XCMPLX_1:59;
verum end; end; end; case A55:
x = 4
;
( x = 4 & y = 4 & z = 4 & t = 4 )end; end; end;
hence
( (
x = 2 &
y = 3 &
z = 7 &
t = 42 ) or (
x = 2 &
y = 3 &
z = 8 &
t = 24 ) or (
x = 2 &
y = 3 &
z = 9 &
t = 18 ) or (
x = 2 &
y = 3 &
z = 10 &
t = 15 ) or (
x = 2 &
y = 3 &
z = 12 &
t = 12 ) or (
x = 2 &
y = 4 &
z = 5 &
t = 20 ) or (
x = 2 &
y = 4 &
z = 6 &
t = 12 ) or (
x = 2 &
y = 4 &
z = 8 &
t = 8 ) or (
x = 2 &
y = 5 &
z = 5 &
t = 10 ) or (
x = 2 &
y = 6 &
z = 6 &
t = 6 ) or (
x = 3 &
y = 3 &
z = 4 &
t = 12 ) or (
x = 3 &
y = 3 &
z = 6 &
t = 6 ) or (
x = 3 &
y = 4 &
z = 4 &
t = 6 ) or (
x = 4 &
y = 4 &
z = 4 &
t = 4 ) )
;
verum
end;
thus
( ( ( x = 2 & y = 3 & z = 7 & t = 42 ) or ( x = 2 & y = 3 & z = 8 & t = 24 ) or ( x = 2 & y = 3 & z = 9 & t = 18 ) or ( x = 2 & y = 3 & z = 10 & t = 15 ) or ( x = 2 & y = 3 & z = 12 & t = 12 ) or ( x = 2 & y = 4 & z = 5 & t = 20 ) or ( x = 2 & y = 4 & z = 6 & t = 12 ) or ( x = 2 & y = 4 & z = 8 & t = 8 ) or ( x = 2 & y = 5 & z = 5 & t = 10 ) or ( x = 2 & y = 6 & z = 6 & t = 6 ) or ( x = 3 & y = 3 & z = 4 & t = 12 ) or ( x = 3 & y = 3 & z = 6 & t = 6 ) or ( x = 3 & y = 4 & z = 4 & t = 6 ) or ( x = 4 & y = 4 & z = 4 & t = 4 ) ) implies (((1 / x) + (1 / y)) + (1 / z)) + (1 / t) = 1 )
; verum