let m be non zero Nat; :: thesis: ex s being Nat st
for n being Nat st n > s holds
((2 |^ m) * (2 |^ (2 |^ n))) + 1 is composite

set k = 2 |^ m;
consider s, z being Nat such that
A1: m = (2 |^ s) * ((2 * z) + 1) by NAGATA_2:1;
set h = (2 * z) + 1;
take s ; :: thesis: for n being Nat st n > s holds
((2 |^ m) * (2 |^ (2 |^ n))) + 1 is composite

let n be Nat; :: thesis: ( n > s implies ((2 |^ m) * (2 |^ (2 |^ n))) + 1 is composite )
assume A2: n > s ; :: thesis: ((2 |^ m) * (2 |^ (2 |^ n))) + 1 is composite
reconsider ns = n - s as non zero Element of NAT by A2, INT_1:5;
0 + 1 <= (2 |^ m) * (2 |^ (2 |^ n)) by NAT_1:13;
then 1 + 1 <= ((2 |^ m) * (2 |^ (2 |^ n))) + 1 by XREAL_1:6;
hence 2 <= ((2 |^ m) * (2 |^ (2 |^ n))) + 1 ; :: according to NUMBER02:def 1 :: thesis: not ((2 |^ m) * (2 |^ (2 |^ n))) + 1 is prime
A3: (2 |^ m) * (2 |^ (2 |^ n)) = (2 |^ m) * (2 |^ (2 |^ n))
.= 2 |^ ((2 |^ (s + ns)) + ((2 |^ s) * ((2 * z) + 1))) by A1, NEWTON:8
.= 2 |^ (((2 |^ s) * (2 |^ ns)) + ((2 |^ s) * ((2 * z) + 1))) by NEWTON:8
.= 2 |^ ((2 |^ s) * ((2 |^ ns) + ((2 * z) + 1)))
.= (2 |^ (2 |^ s)) |^ ((2 |^ ns) + ((2 * z) + 1)) by NEWTON:9 ;
consider z being Nat such that
A4: (2 |^ ns) + ((2 * z) + 1) = (2 * z) + 1 by ABIAN:9;
A5: (2 |^ (2 |^ s)) + (1 |^ ((2 |^ ns) + ((2 * z) + 1))) divides ((2 |^ m) * (2 |^ (2 |^ n))) + (1 |^ ((2 |^ ns) + ((2 * z) + 1))) by A3, A4, NEWTON01:35;
A6: not 2 is trivial by NAT_2:def 1;
then 2 |^ 0 < 2 |^ m by NAT_6:2;
then A7: 1 < 2 |^ m by NEWTON:4;
2 |^ s < 2 |^ n by A2, A6, NAT_6:2;
then 2 |^ (2 |^ s) < 2 |^ (2 |^ n) by A6, NAT_6:2;
then 1 * (2 |^ (2 |^ s)) < (2 |^ m) * (2 |^ (2 |^ n)) by A7, XREAL_1:96;
then A8: (2 |^ (2 |^ s)) + 1 < ((2 |^ m) * (2 |^ (2 |^ n))) + 1 by XREAL_1:6;
(2 |^ (2 |^ s)) + 1 > 0 + 1 by XREAL_1:6;
hence not ((2 |^ m) * (2 |^ (2 |^ n))) + 1 is prime by A5, A8; :: thesis: verum