let k, m be Nat; for p being Prime st p <= k holds
(multiples p) /\ (seq (k,m)) misses primeNumbers (k,m)
let p be Prime; ( p <= k implies (multiples p) /\ (seq (k,m)) misses primeNumbers (k,m) )
set A = primeNumbers (k,m);
set D = (multiples p) /\ (seq (k,m));
assume A1:
p <= k
; (multiples p) /\ (seq (k,m)) misses primeNumbers (k,m)
assume
(multiples p) /\ (seq (k,m)) meets primeNumbers (k,m)
; contradiction
then consider x being object such that
A2:
x in (multiples p) /\ (seq (k,m))
and
A3:
x in primeNumbers (k,m)
by XBOOLE_0:3;
A4:
x is Multiple of p
by A2, Th61;
x in seq (k,m)
by A2;
then consider n being Element of NAT such that
A5:
x = n
and
A6:
k + 1 <= n
and
n <= k + m
;
A7:
p + 1 <= k + 1
by A1, XREAL_1:6;
n is prime
by A3, A5, NEWTON:def 6;
then
( p = 1 or p = n )
by A4, A5, Def15;
then
p + 1 <= p + 0
by A6, A7, XXREAL_0:2, INT_2:def 4;
hence
contradiction
by XREAL_1:6; verum