let x, y, z, t be Nat; ( not x,y are_coprime or (x ^2) + (6 * (y ^2)) <> z ^2 or (6 * (x ^2)) + (y ^2) <> t ^2 )
assume A1:
x,y are_coprime
; ( (x ^2) + (6 * (y ^2)) <> z ^2 or (6 * (x ^2)) + (y ^2) <> t ^2 )
assume A2:
( (x ^2) + (6 * (y ^2)) = z ^2 & (6 * (x ^2)) + (y ^2) = t ^2 )
; contradiction
then
7 * ((x ^2) + (y ^2)) = (z ^2) + (t ^2)
;
then
7 divides (z ^2) + (t ^2)
;
then A3:
( 7 divides z & 7 divides t )
by NUMBER02:52;
then
7 divides z + t
by NAT_D:8;
then A4:
7 * 7 divides (z + t) * (z + t)
by NAT_3:1;
A5:
7 * 7 divides z * t
by A3, NAT_3:1;
z * t divides 2 * (z * t)
;
then
7 * 7 divides 2 * (z * t)
by A5, INT_2:9;
then
7 * 7 divides ((7 * ((x ^2) + (y ^2))) + ((2 * z) * t)) - (2 * (z * t))
by A2, A4, INT_5:1;
then
7 divides (x ^2) + (y ^2)
by INT_4:7;
then
( 7 divides x & 7 divides y )
by NUMBER02:52;
hence
contradiction
by A1, PYTHTRIP:def 1; verum