set A = { [x,y,z] where x, y, z is Integer : ( (x + y) + z = 3 & ((x |^ 3) + (y |^ 3)) + (z |^ 3) = 3 ) } ;
set B = {[1,1,1],[(- 5),4,4],[4,(- 5),4],[4,4,(- 5)]};
A1:
(- 5) |^ 3 = ((- 5) * (- 5)) * (- 5)
by POLYEQ_5:2;
A2:
4 |^ 3 = (4 * 4) * 4
by POLYEQ_5:2;
thus
{ [x,y,z] where x, y, z is Integer : ( (x + y) + z = 3 & ((x |^ 3) + (y |^ 3)) + (z |^ 3) = 3 ) } c= {[1,1,1],[(- 5),4,4],[4,(- 5),4],[4,4,(- 5)]}
XBOOLE_0:def 10 {[1,1,1],[(- 5),4,4],[4,(- 5),4],[4,4,(- 5)]} c= { [x,y,z] where x, y, z is Integer : ( (x + y) + z = 3 & ((x |^ 3) + (y |^ 3)) + (z |^ 3) = 3 ) } proof
let a be
object ;
TARSKI:def 3 ( not a in { [x,y,z] where x, y, z is Integer : ( (x + y) + z = 3 & ((x |^ 3) + (y |^ 3)) + (z |^ 3) = 3 ) } or a in {[1,1,1],[(- 5),4,4],[4,(- 5),4],[4,4,(- 5)]} )
assume
a in { [x,y,z] where x, y, z is Integer : ( (x + y) + z = 3 & ((x |^ 3) + (y |^ 3)) + (z |^ 3) = 3 ) }
;
a in {[1,1,1],[(- 5),4,4],[4,(- 5),4],[4,4,(- 5)]}
then consider x,
y,
z being
Integer such that A3:
a = [x,y,z]
and A4:
(x + y) + z = 3
and A5:
((x |^ 3) + (y |^ 3)) + (z |^ 3) = 3
;
A6:
3
|^ 3
= (3 * 3) * 3
by POLYEQ_5:2;
(
x |^ 3
= (x * x) * x &
y |^ 3
= (y * y) * y &
z |^ 3
= (z * z) * z &
((x + y) + z) |^ 3
= (((x + y) + z) * ((x + y) + z)) * ((x + y) + z) )
by POLYEQ_5:2;
then
(((x + y) + z) |^ 3) - (((x |^ 3) + (y |^ 3)) + (z |^ 3)) = ((3 * (x + y)) * (x + z)) * (y + z)
;
then
27
- 3
= ((3 * (x + y)) * (x + z)) * (y + z)
by A4, A5, A6;
then A7: 8 =
((x + y) * (x + z)) * (y + z)
.=
((3 - z) * (3 - y)) * (3 - x)
by A4
;
then A8:
((3 - x) * (3 - y)) * (3 - z) = 8
;
((3 - z) + (3 - y)) + (3 - x) = 2
* 3
by A4;
per cases then
( ( 3 - z is even & 3 - y is even & 3 - x is even ) or ( 3 - z is even & 3 - y is odd & 3 - x is odd ) or ( 3 - z is odd & 3 - y is even & 3 - x is odd ) or ( 3 - z is odd & 3 - y is odd & 3 - x is even ) )
;
suppose
( 3
- z is
even & 3
- y is
even & 3
- x is
even )
;
a in {[1,1,1],[(- 5),4,4],[4,(- 5),4],[4,4,(- 5)]}then
( ( 3
- x = 2 & 3
- y = 2 & 3
- z = 2 ) or ( 3
- x = - 2 & 3
- y = - 2 & 3
- z = 2 ) or ( 3
- x = - 2 & 3
- y = 2 & 3
- z = - 2 ) or ( 3
- x = 2 & 3
- y = - 2 & 3
- z = - 2 ) )
by A7, Lm11;
hence
a in {[1,1,1],[(- 5),4,4],[4,(- 5),4],[4,4,(- 5)]}
by A3, A4, ENUMSET1:def 2;
verum end; suppose
( 3
- z is
even & 3
- y is
odd & 3
- x is
odd )
;
a in {[1,1,1],[(- 5),4,4],[4,(- 5),4],[4,4,(- 5)]}then
( ( 3
- z = 8 & 3
- y = 1 & 3
- x = 1 ) or ( 3
- z = 8 & 3
- y = - 1 & 3
- x = - 1 ) or ( 3
- z = - 8 & 3
- y = 1 & 3
- x = - 1 ) or ( 3
- z = - 8 & 3
- y = - 1 & 3
- x = 1 ) )
by A7, Lm12;
hence
a in {[1,1,1],[(- 5),4,4],[4,(- 5),4],[4,4,(- 5)]}
by A3, A4, ENUMSET1:def 2;
verum end; suppose
( 3
- z is
odd & 3
- y is
even & 3
- x is
odd )
;
a in {[1,1,1],[(- 5),4,4],[4,(- 5),4],[4,4,(- 5)]}then
( ( 3
- y = 8 & 3
- z = 1 & 3
- x = 1 ) or ( 3
- y = 8 & 3
- z = - 1 & 3
- x = - 1 ) or ( 3
- y = - 8 & 3
- z = 1 & 3
- x = - 1 ) or ( 3
- y = - 8 & 3
- z = - 1 & 3
- x = 1 ) )
by A7, Lm12;
hence
a in {[1,1,1],[(- 5),4,4],[4,(- 5),4],[4,4,(- 5)]}
by A3, A4, ENUMSET1:def 2;
verum end; suppose
( 3
- z is
odd & 3
- y is
odd & 3
- x is
even )
;
a in {[1,1,1],[(- 5),4,4],[4,(- 5),4],[4,4,(- 5)]}then
( ( 3
- x = 8 & 3
- y = 1 & 3
- z = 1 ) or ( 3
- x = 8 & 3
- y = - 1 & 3
- z = - 1 ) or ( 3
- x = - 8 & 3
- y = 1 & 3
- z = - 1 ) or ( 3
- x = - 8 & 3
- y = - 1 & 3
- z = 1 ) )
by A8, Lm12;
hence
a in {[1,1,1],[(- 5),4,4],[4,(- 5),4],[4,4,(- 5)]}
by A3, A4, ENUMSET1:def 2;
verum end; end;
end;
let a be object ; TARSKI:def 3 ( not a in {[1,1,1],[(- 5),4,4],[4,(- 5),4],[4,4,(- 5)]} or a in { [x,y,z] where x, y, z is Integer : ( (x + y) + z = 3 & ((x |^ 3) + (y |^ 3)) + (z |^ 3) = 3 ) } )
assume
a in {[1,1,1],[(- 5),4,4],[4,(- 5),4],[4,4,(- 5)]}
; a in { [x,y,z] where x, y, z is Integer : ( (x + y) + z = 3 & ((x |^ 3) + (y |^ 3)) + (z |^ 3) = 3 ) }
then A9:
( a = [1,1,1] or a = [(- 5),4,4] or a = [4,(- 5),4] or a = [4,4,(- 5)] )
by ENUMSET1:def 2;
( ((- 5) + 4) + 4 = 3 & (4 + 4) + (- 5) = 3 & ((1 |^ 3) + (1 |^ 3)) + (1 |^ 3) = 3 & ((4 |^ 3) + ((- 5) |^ 3)) + (4 |^ 3) = 3 & ((4 |^ 3) + (4 |^ 3)) + ((- 5) |^ 3) = 3 )
by A1, A2;
hence
a in { [x,y,z] where x, y, z is Integer : ( (x + y) + z = 3 & ((x |^ 3) + (y |^ 3)) + (z |^ 3) = 3 ) }
by A9; verum