let m, n be Nat; ( not m * n = 626 or ( m = 1 & n = 626 ) or ( m = 2 & n = 313 ) or ( m = 313 & n = 2 ) or ( m = 626 & n = 1 ) )
assume A1:
m * n = 626
; ( ( m = 1 & n = 626 ) or ( m = 2 & n = 313 ) or ( m = 313 & n = 2 ) or ( m = 626 & n = 1 ) )
m divides m * n
;
then
( m = 1 or m = 2 or m = 313 or m = 626 )
by A1, Th25;
hence
( ( m = 1 & n = 626 ) or ( m = 2 & n = 313 ) or ( m = 313 & n = 2 ) or ( m = 626 & n = 1 ) )
by A1; verum