let m, n be Nat; ( not m * n = 362 or ( m = 1 & n = 362 ) or ( m = 2 & n = 181 ) or ( m = 181 & n = 2 ) or ( m = 362 & n = 1 ) )
assume A1:
m * n = 362
; ( ( m = 1 & n = 362 ) or ( m = 2 & n = 181 ) or ( m = 181 & n = 2 ) or ( m = 362 & n = 1 ) )
m divides m * n
;
then
( m = 1 or m = 2 or m = 181 or m = 362 )
by A1, Th23;
hence
( ( m = 1 & n = 362 ) or ( m = 2 & n = 181 ) or ( m = 181 & n = 2 ) or ( m = 362 & n = 1 ) )
by A1; verum