let k be Nat; for p being Prime st p * p <= k & k < 49 & not p = 2 & not p = 3 holds
p = 5
let p be Prime; ( p * p <= k & k < 49 & not p = 2 & not p = 3 implies p = 5 )
assume
( p * p <= k & k < 49 )
; ( p = 2 or p = 3 or p = 5 )
then
p * p < 7 * 7
by XXREAL_0:2;
hence
( p = 2 or p = 3 or p = 5 )
by Th5, NAT_4:1; verum