let s1, s2 be XFinSequence of NAT ; :: thesis: for n being Nat st len s1 = n + 1 & ( for i being Nat st i in dom s1 holds
s1 . i = i |^ 5 ) & len s2 = n + 1 & ( for i being Nat st i in dom s2 holds
s2 . i = i |^ 3 ) holds
Sum s2 divides 3 * (Sum s1)

let n be Nat; :: thesis: ( len s1 = n + 1 & ( for i being Nat st i in dom s1 holds
s1 . i = i |^ 5 ) & len s2 = n + 1 & ( for i being Nat st i in dom s2 holds
s2 . i = i |^ 3 ) implies Sum s2 divides 3 * (Sum s1) )

assume that
s1: ( len s1 = n + 1 & ( for i being Nat st i in dom s1 holds
s1 . i = i |^ 5 ) ) and
s2: ( len s2 = n + 1 & ( for i being Nat st i in dom s2 holds
s2 . i = i |^ 3 ) ) ; :: thesis: Sum s2 divides 3 * (Sum s1)
deffunc H1( Nat) -> set = $1 |^ 3;
consider S2 being Real_Sequence such that
S2: for i being Nat holds S2 . i = H1(i) from SEQ_1:sch 1();
( Segm (n + 1) c= NAT & dom S2 = NAT ) by PARTFUN1:def 2;
then dom (S2 | (Segm (n + 1))) = Segm (n + 1) ;
then dr: dom (S2 | (Segm (n + 1))) = dom s2 by s2;
now :: thesis: for o being object st o in dom s2 holds
s2 . o = (S2 | (Segm (n + 1))) . o
let o be object ; :: thesis: ( o in dom s2 implies s2 . o = (S2 | (Segm (n + 1))) . o )
assume o: o in dom s2 ; :: thesis: s2 . o = (S2 | (Segm (n + 1))) . o
then o in Segm (n + 1) by s2;
then o is natural ;
then reconsider on = o as Nat by TARSKI:1;
thus s2 . o = on |^ 3 by s2, o
.= S2 . on by S2
.= (S2 | (Segm (n + 1))) . o by o, dr, FUNCT_1:47 ; :: thesis: verum
end;
then s2 = S2 | (Segm (n + 1)) by dr, FUNCT_1:2;
then Sum s2 = (Partial_Sums S2) . n by RVSUM_4:4;
then ss: Sum s2 = ((n |^ 2) * ((n + 1) |^ 2)) / 4 by S2, SERIES_2:15;
deffunc H2( Nat) -> set = $1 |^ 5;
consider S1 being Real_Sequence such that
S1: for i being Nat holds S1 . i = H2(i) from SEQ_1:sch 1();
( Segm (n + 1) c= NAT & dom S1 = NAT ) by PARTFUN1:def 2;
then dom (S1 | (Segm (n + 1))) = Segm (n + 1) ;
then ds: dom (S1 | (Segm (n + 1))) = dom s1 by s1;
now :: thesis: for o being object st o in dom s1 holds
s1 . o = (S1 | (Segm (n + 1))) . o
let o be object ; :: thesis: ( o in dom s1 implies s1 . o = (S1 | (Segm (n + 1))) . o )
assume o: o in dom s1 ; :: thesis: s1 . o = (S1 | (Segm (n + 1))) . o
then o in Segm (n + 1) by s1;
then o is natural ;
then reconsider on = o as Nat by TARSKI:1;
thus s1 . o = on |^ 5 by s1, o
.= S1 . on by S1
.= (S1 | (Segm (n + 1))) . o by o, ds, FUNCT_1:47 ; :: thesis: verum
end;
then s1 = S1 | (Segm (n + 1)) by ds, FUNCT_1:2;
then Sum s1 = (Partial_Sums S1) . n by RVSUM_4:4;
then Sum s1 = (((n |^ 2) * ((n + 1) |^ 2)) * (((2 * (n |^ 2)) + (2 * n)) - 1)) / 12 by S1, SERIES_2:19;
then 3 * (Sum s1) = (((2 * (n |^ 2)) + (2 * n)) - 1) * (Sum s2) by ss;
hence Sum s2 divides 3 * (Sum s1) by INT_1:def 3; :: thesis: verum