let A be set ; for X being non empty set
for f being Function of X,[:(Fin A),(Fin A):]
for B being Element of Fin X
for x being Element of X st x in B holds
f . x c= FinPairUnion (B,f)
let X be non empty set ; for f being Function of X,[:(Fin A),(Fin A):]
for B being Element of Fin X
for x being Element of X st x in B holds
f . x c= FinPairUnion (B,f)
let f be Function of X,[:(Fin A),(Fin A):]; for B being Element of Fin X
for x being Element of X st x in B holds
f . x c= FinPairUnion (B,f)
let B be Element of Fin X; for x being Element of X st x in B holds
f . x c= FinPairUnion (B,f)
let x be Element of X; ( x in B implies f . x c= FinPairUnion (B,f) )
assume A1:
x in B
; f . x c= FinPairUnion (B,f)
then (FinPairUnion A) $$ (B,f) =
(FinPairUnion A) $$ ((B \/ {.x.}),f)
by ZFMISC_1:40
.=
(FinPairUnion A) . (((FinPairUnion A) $$ (B,f)),(f . x))
by A1, SETWISEO:20
.=
((FinPairUnion A) $$ (B,f)) \/ (f . x)
by Def6
;
hence
f . x c= FinPairUnion (B,f)
by Th10; verum