let D be non empty set ; for fD being PFuncs (D,D) -valued FinSequence
for fB being PFuncs (D,BOOLEAN) -valued FinSequence st fD,fB are_composable holds
<*(fB . 1),(PP_composition fD),(fB . (len fB))*> is SFHT of D
let fD be PFuncs (D,D) -valued FinSequence; for fB being PFuncs (D,BOOLEAN) -valued FinSequence st fD,fB are_composable holds
<*(fB . 1),(PP_composition fD),(fB . (len fB))*> is SFHT of D
let fB be PFuncs (D,BOOLEAN) -valued FinSequence; ( fD,fB are_composable implies <*(fB . 1),(PP_composition fD),(fB . (len fB))*> is SFHT of D )
assume that
A1:
1 <= len fD
and
A2:
len fB = (len fD) + 1
and
A3:
for n being Nat st 1 <= n & n <= len fD holds
<*(fB . n),(fD . n),(fB . (n + 1))*> is SFHT of D
and
A4:
for n being Nat st 2 <= n & n <= len fD holds
<*(PP_inversion (fB . n)),(fD . n),(fB . (n + 1))*> is SFHT of D
; NOMIN_8:def 7 <*(fB . 1),(PP_composition fD),(fB . (len fB))*> is SFHT of D
set G = PP_compositionSeq fD;
defpred S1[ Nat] means ( 1 <= $1 & $1 <= len fD implies <*(fB . 1),((PP_compositionSeq fD) . $1),(fB . ($1 + 1))*> is SFHT of D );
A5:
S1[ 0 ]
;
A6:
for k being Nat st S1[k] holds
S1[k + 1]
proof
let k be
Nat;
( S1[k] implies S1[k + 1] )
assume that A7:
S1[
k]
and A8:
1
<= k + 1
and A9:
k + 1
<= len fD
;
<*(fB . 1),((PP_compositionSeq fD) . (k + 1)),(fB . ((k + 1) + 1))*> is SFHT of D
per cases
( k = 0 or k > 0 )
;
suppose
k > 0
;
<*(fB . 1),((PP_compositionSeq fD) . (k + 1)),(fB . ((k + 1) + 1))*> is SFHT of Dthen A11:
0 + 1
<= k
by NAT_1:13;
A12:
k < len fD
by A9, NAT_1:13;
A13:
k <= k + 1
by NAT_1:11;
A14:
<*(fB . (k + 1)),(fD . (k + 1)),(fB . ((k + 1) + 1))*> is
SFHT of
D
by A3, A8, A9;
<*(PP_inversion (fB . (k + 1))),(fD . (k + 1)),(fB . ((k + 1) + 1))*> is
SFHT of
D
by A4, A9, A11, XREAL_1:6;
then
<*(fB . 1),(PP_composition (((PP_compositionSeq fD) . k),(fD . (k + 1)))),(PP_or ((fB . ((k + 1) + 1)),(fB . ((k + 1) + 1))))*> is
SFHT of
D
by A7, A9, A11, A13, A14, XXREAL_0:2, NOMIN_3:24;
hence
<*(fB . 1),((PP_compositionSeq fD) . (k + 1)),(fB . ((k + 1) + 1))*> is
SFHT of
D
by A11, A12, Def5;
verum end; end;
end;
A15:
for k being Nat holds S1[k]
from NAT_1:sch 2(A5, A6);
len (PP_compositionSeq fD) = len fD
by A1, Def5;
hence
<*(fB . 1),(PP_composition fD),(fB . (len fB))*> is SFHT of D
by A1, A2, A15; verum