let a, b be Integer; ( a,b are_coprime implies ((a - b) * (a + b)) gcd (a * b) = 1 )
assume A1:
a,b are_coprime
; ((a - b) * (a + b)) gcd (a * b) = 1
( a gcd b = a gcd (b - (1 * a)) & a gcd b = a gcd (b + (1 * a)) )
by NEWTON02:5;
then
( (- (a - b)) gcd a = 1 & (a + b) gcd a = 1 )
by A1;
then
( a - b,a are_coprime & a + b,a are_coprime )
by NEWTON02:1;
then A2:
(a - b) * (a + b),a are_coprime
by INT_2:26;
( b gcd a = b gcd (a - (1 * b)) & b gcd a = b gcd (a + (1 * b)) )
by NEWTON02:5;
then
( a - b,b are_coprime & a + b,b are_coprime )
by A1;
then
(a - b) * (a + b),b are_coprime
by INT_2:26;
then
(a - b) * (a + b),a * b are_coprime
by A2, INT_2:26;
hence
((a - b) * (a + b)) gcd (a * b) = 1
; verum