let a, b be non zero Integer; for c being non trivial Nat holds c |-count (a gcd b) = min ((c |-count a),(c |-count b))
let c be non trivial Nat; c |-count (a gcd b) = min ((c |-count a),(c |-count b))
A1:
|.c.| > 1
by NEWTON03:def 1;
then A3:
( c |^ (c |-count a) divides a & not c |^ ((c |-count a) + 1) divides a )
by NEWTON03:def 7;
A4:
( c |^ (c |-count b) divides b & not c |^ ((c |-count b) + 1) divides b )
by A1, NEWTON03:def 7;
A5:
( |.(c |^ ((c |-count b) + 1)).| in NAT & |.a.| in NAT & |.b.| in NAT )
by INT_1:3;
per cases
( c |-count a >= c |-count b or c |-count b > c |-count a )
;
suppose B1:
c |-count a >= c |-count b
;
c |-count (a gcd b) = min ((c |-count a),(c |-count b))then B2:
min (
(c |-count a),
(c |-count b))
= c |-count b
by XXREAL_0:def 9;
c |^ (c |-count b) divides c |^ (c |-count a)
by B1, NEWTON:89;
then
c |^ (c |-count b) divides a
by A3, INT_2:9;
then B3:
c |^ (c |-count b) divides a gcd b
by A4, INT_2:def 2;
not
|.(c |^ ((c |-count b) + 1)).| divides |.b.|
by A4, INT_2:16;
then
not
|.(c |^ ((c |-count b) + 1)).| divides |.a.| gcd |.b.|
by A5, NEWTON:50;
then
not
c |^ ((c |-count b) + 1) divides a gcd b
by INT_2:34;
hence
c |-count (a gcd b) = min (
(c |-count a),
(c |-count b))
by A1, B2, B3, NEWTON03:def 7;
verum end; suppose B1:
c |-count b > c |-count a
;
c |-count (a gcd b) = min ((c |-count a),(c |-count b))then B2:
min (
(c |-count b),
(c |-count a))
= c |-count a
by XXREAL_0:def 9;
c |^ (c |-count a) divides c |^ (c |-count b)
by B1, NEWTON:89;
then
c |^ (c |-count a) divides b
by A4, INT_2:9;
then B3:
c |^ (c |-count a) divides a gcd b
by A3, INT_2:def 2;
not
|.(c |^ ((c |-count a) + 1)).| divides |.a.|
by A3, INT_2:16;
then
not
|.(c |^ ((c |-count a) + 1)).| divides |.a.| gcd |.b.|
by A5, NEWTON:50;
then
not
c |^ ((c |-count a) + 1) divides a gcd b
by INT_2:34;
hence
c |-count (a gcd b) = min (
(c |-count a),
(c |-count b))
by A1, B2, B3, NEWTON03:def 7;
verum end; end;