let a, b, m, n be Nat; Sum ((a,b) In_Power (m + n)) = (Sum ((a,b) In_Power m)) * (Sum ((a,b) In_Power n))
Sum ((a,b) In_Power (m + n)) =
(a + b) |^ (m + n)
by NEWTON:30
.=
((a + b) |^ m) * ((a + b) |^ n)
by NEWTON:8
.=
(Sum ((a,b) In_Power m)) * ((a + b) |^ n)
by NEWTON:30
.=
(Sum ((a,b) In_Power m)) * (Sum ((a,b) In_Power n))
by NEWTON:30
;
hence
Sum ((a,b) In_Power (m + n)) = (Sum ((a,b) In_Power m)) * (Sum ((a,b) In_Power n))
; verum